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            • 1. 已知函数\(f(x){=}\dfrac{a{⋅}2^{x}{+}b{+}1}{2^{x}{+}1}\)是定义域在\(R\)上的奇函数,且\(f(2){=}\dfrac{6}{5}\).
              \((1)\)求实数\(a\)、\(b\)的值;
              \((2)\)判断函数\(f(x)\)的单调性,并用定义证明;
              \((3)\)解不等式:\(f(\log{{ }}_{\frac{1}{2}}(2x{-}2){]+}f{[}\log_{2}(1{-}\dfrac{1}{2}x){]\geqslant }0\).
            • 2.

              计算下列各式的值:

              \((1)1.{5}^{ \frac{1}{3}}×\left(- \dfrac{7}{6}\right)+{8}^{0.25}× \sqrt{{\left( \dfrac{2}{3}\right)}^{ \frac{2}{3}}} \);

              \((2) \dfrac{1}{2}1g \dfrac{32}{49}1g \sqrt{8}+1g \sqrt{245}+{10}^{1g3} \).

            • 3.

              已知定义域为\(R\)的函数\(f(x)= \dfrac{n-{2}^{x}}{{2}^{x+1}+m} \)是奇函数.

              \((\)Ⅰ\()\)求\(m\),\(n\)的值;

              \((\)Ⅱ\()\)当\(x∈[ \dfrac{1}{2},3] \)时,\(f(kx^{2})+f(2x-1) > 0\)恒成立,求实数\(k\)的取值范围.

            • 4. 计算:
              \((1)(\sqrt[3]{2}{×}\sqrt{3})^{6}{+}(\sqrt{2\sqrt{2}}){{ }}^{\frac{4}{3}}{-}4{×}(\dfrac{16}{49}){{ }}^{{-}\frac{1}{2}}{-}\sqrt[4]{2}{×}8^{0{.}25}{-}({-}2005)^{0}(2)\dfrac{(1{-}\log_{6}3)^{2}{+}\log_{6}2{⋅}\log_{6}18}{\log_{6}4}\)
            • 5. \((\)Ⅰ\()(0.064)\)\(-(-\)\()^{0}+[(-2)^{3}]\)\(+(16)^{-0.75}\)
              \((\)Ⅱ\()\) \(\log \)\({\,\!}_{3}\)\(+\) \(\lg \)\(25+\) \(\lg \)\(4+7\)\(+(-9.8)^{0}\).
            • 6.

              \((\)Ⅰ\()\)求值:\(0.{16}^{- \frac{1}{2}}-{\left(2009\right)}^{0}+{16}^{ \frac{3}{4}}+{\log }_{2} \sqrt{2} \);        

              \((\)Ⅱ\()\)方程:\({\left({\log }_{2}x\right)}^{2}-2{\log }_{2}x-3=0 \),求\(x\)的值.

            • 7. \((1)\)计算\((5 \dfrac {1}{16})^{0.5}-2×(2 \dfrac {10}{27})^{- \frac {2}{3}}-2×( \sqrt {2+π})^{0}÷( \dfrac {3}{4})^{-2}\)
              \((2)\)计算\(9^{\log _{3}2}-4\log _{4}3\cdot \log _{27}8+ \dfrac {1}{3}\log _{6}8-2\log _{6^{-1}} \sqrt {3}\).
            • 8.

              设函数\(f\left( x \right)={{2}^{x}}\) ,函数\(g\left( x \right)\) 的图像与函数\(f\left( x \right)\) 的图像关于\(y\) 轴对称.

              \((1)\)若\(f\left( x \right)=4g\left( x \right)+3\) ,求\(x\) 的值;

              \((2)\)若存在\(x\in \left[ 0,4 \right]\) ,使不等式\(f\left( a+x \right)-g\left( -2x \right)\geqslant 3\) 成立,求实数\(a\) 的取值范围.

            • 9.
              计算:
              \((1)\)计算\(27\;^{ \frac {2}{3}}-2\;^{\log _{2}3}×\log _{2} \dfrac {1}{8}+\log _{2}3×\log _{3}4\);
              \((2)\)已知\(0 < x < 1\),\(x+x^{-1}=3\),求\(x\;^{ \frac {1}{2}}-x\;^{- \frac {1}{2}}\).
            • 10.
              计算下列各式的值:
              \((1)( \dfrac {2}{3})^{-2}+(1- \sqrt {2})^{0}-(3 \dfrac {3}{8})^{ \frac {2}{3}}\);
              \((2) \dfrac {2\lg 2+\lg 3}{1+ \dfrac {1}{2}\lg 0.36+ \dfrac {1}{3}\lg 8}\).
            0/40

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