共50条信息
若\({{x}^{2018}}={{a}_{0}}+{{a}_{1}}(x-1)+{{a}_{2}}{{(x-1)}^{2}}+\cdot \cdot \cdot +{{a}_{2018}}{{(x-1)}^{2018}},\)则\(\dfrac{{{a}_{1}}}{3}+\dfrac{{{a}_{2}}}{{{3}^{2}}}+\cdot \cdot \cdot +\dfrac{{{a}_{2018}}}{{{3}^{2018}}}=\)_____.
已知函数\(f\left( x \right)\)由以下表给出,若\(f\left\lbrack f\left( x_{0} \right) \right\rbrack{=}f\left( 1 \right){+}f\left( 3 \right)\),则\(x_{0}{=}(\) \()\)
\(x\)
\(1\)
\(2\)
\(3\)
\(4\)
\(f\left( x \right)\)
\({-}1\)
设函数\(f(x)\)是定义在\(R\)上的奇函数,且\(f(x)=\begin{cases} & {{\log }_{2}}(x+1),x\geqslant 0 \\ & g(x),x < 0 \\ \end{cases}\),则\(g[f(-7)]=\)( )
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