优优班--学霸训练营 > 知识点挑题
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            • 1.

              已知向量\( \overrightarrow{a}=\left(3,1\right) \),\( \overrightarrow{b}=\left(-2,4\right) \),求\( \overrightarrow{a} \)在\( \overrightarrow{b} \)方向上的投影为         

            • 2.

              \((1)\)已知向量\(\overset{}{a}\),\(\overset{}{b}\),若\(\overset{}{a}\)在\(\overset{}{b}\)方向上的投影为\(3\),\(\left| \overset{}{b} \right|{=}2\),则\(\overrightarrow{a}\cdot \overrightarrow{b}=\)__________.

              \((2)\)若函数\(f(x)=\sin \pi x,x\in [\dfrac{1}{3},\dfrac{5}{6}]\),则\(f(x)\)的值域为___________.

              \((3)\)已知\(\cos (\dfrac{\pi }{6}-\alpha )=\dfrac{2}{3}\),则\(\sin (\alpha -\dfrac{2\pi }{3})=\)__________.

              \((4)\)若函数\(f(x)=\dfrac{2{{(x+1)}^{2}}+\sin x}{{{x}^{2}}+1}\)的最大值和最小值分别为\(M\)、\(m\),则函数\(M+m=\)_______.

            • 3. 已知\(\left| \overrightarrow{a} \right|=2,\left| \overrightarrow{b} \right|=\sqrt{3},\left( \overrightarrow{a}+2\overrightarrow{b} \right)\cdot \left( \overrightarrow{b}-3\overrightarrow{a} \right)=9\)

              \((1)\)求\(\overrightarrow{a}\cdot \overrightarrow{b}\) ;

              \((2)\)在\(\Delta ABC\),\(\overrightarrow{AB}=\overrightarrow{a},\overrightarrow{AC}=\overrightarrow{b}\) ,求\(BC\)边的长度和\(\overrightarrow{AB}\) 在\(\overrightarrow{AC}\) 上的投影.

            • 4.

              已知在正方形\(ABCD\)中,\(\overset{⇀}{AE}= \dfrac{1}{2} \overset{⇀}{AB} \),\(\overset{⇀}{AF}= \dfrac{1}{4} \overset{⇀}{AD} \),则\(\overset{⇀}{CE} \)在\(\overset{⇀}{CF} \)方向上的投影为\((\)   \()\)

              A.\(4\)   
              B.\(\dfrac{22}{5} \)
              C.\(2 \sqrt{5} \)
              D.\(\dfrac{11 \sqrt{5}}{5} \)
            • 5.

              已知点\(A(-1,1)\),\(B(1,2)\),\(C(-2,-1)\),\(D(3,4)\),则向量\(\overrightarrow{CD}\)在\(\overrightarrow{BA}\)方向上的投影是\((\)  \()\)

              A.\(-3 \sqrt{5}\)
              B.\(- \dfrac{3 \sqrt{2}}{2}\)

              C.\(3 \sqrt{5}\)
              D.\( \dfrac{3 \sqrt{2}}{2}\)
            • 6.

              \(\triangle ABC\)的外接圆的圆心为\(O\),半径为\(1\),\(2\overrightarrow{AO}=\overrightarrow{AB}+\overrightarrow{AC}\),且\(|\overrightarrow{OA}|=|\overrightarrow{AB}|\),则向量\(\overrightarrow{CA}\)在向量\(\overrightarrow{CB}\)方向上的投影为

              A.\(\dfrac{1}{2}\)
              B.\(-\dfrac{3}{2}\)
              C.\(-\dfrac{1}{2}\)
              D.\(\dfrac{3}{2}\)
            • 7.

              已知向量\( \overset{→}{a} =(-2,1)\),\( \overset{→}{b} =(3,0)\),则\( \overset{→}{a} \)在\( \overset{→}{b} \)方向上的正射影的数量为(    )

              A.\(- \sqrt{5} \)
              B.\( \sqrt{5} \)​
              C.\(-2\)
              D.\(2\)
            • 8.

              若锐角\(α\)、\(β\)满足\((1+ \sqrt{3} \)\(\tan \)\(α)(1+ \sqrt{3} \)\(\tan \)\(β)=4\),则\(α+β= \)______.



              已知\(2 \overset{→}{a} - \overset{→}{b} =(-1, \sqrt{3} )\),\( \overset{→}{c} =(1, \sqrt{3} )\)且\( \overset{→}{a} · \overset{→}{c} =3\),\(| \overset{→}{b} |=4\),则\( \overset{→}{b} \)与\( \overset{→}{c} \)的夹角为 ______.



              已知\(x\)\(∈R\),向量\( \overset{→}{AB} =(-1,x+2)\),\( \overset{→}{CD} =(x,1)\),则在\( \overset{→}{AB} \)方向上的投影的最大值为 ______.






              已知函数 \(f\)\(( \)\(x\)\()=\) \(\sin \)\({\,\!}^{2}\) \(x\)\(+\) \(\sin x\cos x\)\(- \dfrac{1}{2} \),下列结论中:
              \(①\)函数 \(f\)\(( \)\(x\)\()\)关于 \(x\)\(= \dfrac{π}{8} \)对称;
              \(②\)函数 \(f\)\(( \)\(x\)\()\)关于\((- \dfrac{π}{8} ,0)\)对称;
              \(③\)函数 \(f\)\(( \)\(x\)\()\)在\((0, \dfrac{π}{8} )\)是增函数,
              \(④\)将 \(y\)\(= \dfrac{ \sqrt{2}}{2} \) \(\cos \)\(2\) \(x\)的图象向右平移\( \dfrac{3π}{8} \)可得到 \(f\)\(( \)\(x\)\()\)的图象.

              其中正确的结论序号为 ______.

            • 9.

              设\(O\)为坐标原点,\(M(2,1)\),点\(N(x,y)\)满足\(\begin{cases} & x-4y\leqslant -3 \\ & 3x+5y\leqslant 25 \\ & x\geqslant 1 \end{cases}\),则\(\overrightarrow{ON}\)在\(\overrightarrow{OM}\)上的投影最大值是______.

            • 10.

              已知点\(A\)\((-1,1)\),\(B\)\((1,2)\),\(C\)\((-2,-1)\),\(D\)\((3,4)\),则向量\( \overrightarrow{AB} \)在\( \overrightarrow{CD} \)方向上的投影为(    )

              A.\(-\)\( \dfrac{3 \sqrt{2}}{2} \)   
              B. \(-\)\( \dfrac{3 \sqrt{15}}{2} \)     
              C.\( \dfrac{3 \sqrt{2}}{2} \)   
              D.\( \dfrac{3 \sqrt{15}}{2} \)
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