已知数\(\{\)\(a_{n}\)\(\}\)的前\(n\)项和为\(S_{n}\),数列\(\{\)\(b_{n}\)\(\}\)为等差数列,\(b\)\({\,\!}_{1}=-1\),\(b_{n}\)\( > 0(\)\(n\)\(\geqslant 2)\),\(b\)\({\,\!}_{2}\)\(S_{n}\)\(+\)\(a_{n}\)\(=2\)且\(3\)\(a\)\({\,\!}_{2}=2\)\(a\)\({\,\!}_{3}+\)\(a\)\({\,\!}_{1}\).
\((1)\)求\(\{\)\(a_{n}\)\(\}\)、\(\{\)\(b_{n}\)\(\}\)的通项公式;
\((2)\)设\({{c}_{n}}=\dfrac{1}{{{a}_{n}}}\),\({{T}_{n}}=\dfrac{{{b}_{1}}}{{{c}_{1}}+1}+\dfrac{{{b}_{2}}}{{{c}_{2}}+1}+\cdots +\dfrac{{{b}_{n}}}{{{c}_{n}}+1}\),证明:\({{T}_{n}} < \dfrac{5}{2}\).