优优班--学霸训练营 > 知识点挑题
全部资源
          排序:
          最新 浏览

          50条信息

            • 1.

              若\(a=\log _{4}5\),则\(2^{a}+2^{-a}=\)________.

            • 2.

              \((1)\) 已知函数\(f(x){=}\begin{cases} 2^{x}{,} & x{\leqslant }0 \\ f(x{-}1){-}1{,} & x{ > }0 \end{cases}\),则\(f(\log_{2}9){=}\) ______ .

              \((2)\)    变量\(x\)、\(y\)满足线性约束条件\(\begin{cases} 2x{+}y{\leqslant }2 \\ x{-}y{\geqslant }0 \\ y{\geqslant }0 \end{cases}\),则使目标函数\(z{=}{ax}{+}y(a{ > }0)\)取得最大值的最优解有无数个,则\(a\)的值为______ .

              \((3)\)     已知焦点\(F\)为抛物线\(y^{2}{=}2{px}(p{ > }0)\)上有一点\(A(m{,}2\sqrt{2})\),以\(A\)为圆心,\(AF\)为半径的圆被\(y\)轴截得的弦长为\(2\sqrt{5}\),则\(m{=}\) ______ .

              \((4)\)     如图,平面四边形\(ABCD\)中,\({AB}{=}{AD}{=}{CD}{=}1\),\({BD}{=}\sqrt{2}\),\({BD}{⊥}{CD}\),将其沿对角线\(BD\)折成四面体\(A{{{{'}}}-}{BCD}\),使平面\(A{{{{'}}}}{BD}{⊥}\)平面\({BCD}{.}\)四面体\(A{{{{'}}}-}{BCD}\)顶点在同一个球面上,则该球的体积为______ .

            • 3.

              已知函数\(f(x)\)是定义在\(R\)上的奇函数,且是以\(2\)为周期的周期函数\(.\)若当\(x∈[0,1)\)时,\(f(x)=2^{x}-1\),则\(f({{\log }_{\frac{1}{2}}}6)\)的值为________.

            • 4.

              \((1)\)关于\(x\)的不等式\(\dfrac{x-1}{x} < 2\)的解集是________.

              \((2)\)\({{(\,\dfrac{16}{81}\,)}^{-\frac{3}{4}}}+{{\log }_{3}}\dfrac{5}{4}+{{\log }_{3}}\dfrac{4}{5}=\)________.

              \((3)\)已知\(f\left( 1-{\cos }x \right)={si}{{{n}}^{2}}x\),则\(f\left( {{x}^{2}} \right)\)的解析式为__________.

              \((4)\)若\(x\in (\,-\infty \,,\,-1\,]\),不等式\((\,m-{{m}^{2}}\,){{4}^{x}}+{{2}^{x}}+1 > 0\)恒成立,则实数\(m\)的取值范围是_______.

            • 5.

              计算:\((1)2 \sqrt{3}× \sqrt[3]{1.5}× \sqrt[6]{12}\)

              \((2)\lg \dfrac{3}{7}+\lg 70-\lg 3- \sqrt{(\lg 3)^{2}-\lg 9+1}\)

              \((3)\)已知\(\tan α=2\),求\(4\sin ^{2}α-3\sin α\cos α-5\cos ^{2}α\)的值.
            • 6.

              计算下列各式的值:

              \((1)2{{\log }_{3}}2-{{\log }_{3}}\dfrac{32}{9}+{{\log }_{3}}8-{{25}^{{{\log }_{5}}3}}\).

              \((2){{[{{({{0.064}^{\frac{1}{5}}})}^{-2.5}}]}^{\frac{2}{3}}}-\sqrt[3]{3\dfrac{3}{8}}-{{\mathrm{ }\!\!\pi\!\!{ }}^{0}}\).

            • 7.

              \((1)\)求值:
              \(①(2 \dfrac{7}{9}{)}^{ \frac{1}{2}}-(2 \sqrt{3}-π{)}^{0}-(2 \dfrac{10}{27}{)}^{- \frac{2}{3}}+0.{25}^{- \frac{3}{2}} \);
              \(②\)已知\(0 < x < 1\),且\(x+x^{-1}=3\),求\({x}^{ \frac{1}{2}}-{x}^{- \frac{1}{2}} \).

              \((2)\)
              \(①\)计算:\({27}^{ \frac{2}{3}}+{16}^{- \frac{1}{2}}-( \dfrac{1}{2}{)}^{-2}-( \dfrac{8}{27}{)}^{- \frac{2}{3}} \);
              \(②\)化简:\(( \sqrt{a-1}{)}^{2}+ \sqrt{(1-a{)}^{2}}+ \sqrt[3]{(1-a{)}^{3}} \).

            • 8.

              化简下列各式:

              \((1)\)\({\left(0.027\right)}^{- \frac{1}{3}}-{\left( \dfrac{1}{7}\right)}^{-2}+{\left(2 \dfrac{7}{9}\right)}^{ \frac{1}{2}}-{\left( \sqrt{2}-1\right)}^{0} \)


              \((2)\)\({{\log }_{3}}\dfrac{\sqrt[4]{27}}{3}+\lg 25+\lg 4+{{7}^{{{\log }_{7}}2}}\)

            • 9.

              \(x+x^{-1}=4\),则\(x^{2}{+}x^{{-}2}= \)______.

            • 10. 已知幂函数\(f(x)=x^{k^{2}-2k-3}(k∈N^{*})\)的图象关于\(y\)轴对称,且在区间\((0,+∞)\)上是减函数,
              \((1)\)求函数\(f(x)\)的解析式;
              \((2)\)若\(a > k\),比较\((\ln a)^{0.7}\)与\((\ln a)^{0.6}\)的大小.
            0/40

            进入组卷