优优班--学霸训练营 > 知识点挑题
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            • 1.
              设\(a > 0\),\(b > 0\),且\(a+b= \dfrac {1}{a}+ \dfrac {1}{b}.\)求证:
              \((1)a+b\geqslant 2\);
              \((2)a^{2}+a < 2\)与\(b^{2}+b < 2\)不可能同时成立.
            • 2.
              若不等式\(x^{2}-2y^{2}\leqslant cx(y-x)\)对任意满足\(x > y > 0\)的实数\(x\)、\(y\)恒成立,则实数\(c\)的最大值为 ______ .
            • 3.
              已知函数\(f(x)=m-|x-1|\),\(m∈R\),且\(f(x+2)+f(x-2)\geqslant 0\)的解集为\([-2,4]\).
              \((1)\)求\(m\)的值;
              \((2)\)若\(a\),\(b\),\(c\)为正数,且\( \dfrac {1}{a}+ \dfrac {1}{2b}+ \dfrac {1}{3c}=m\),求证\(a+2b+3c\geqslant 3\).
            • 4.
              已知函数\(f(x)=|x+3|+|x-1|\)的最小值为\(m\).
              \((1)\)求\(m\)的值;
              \((2)\)若\(a > 0\),\(b > 0\),\(a+b=m\),求证\( \dfrac {1}{a}+ \dfrac {4}{b}\geqslant \dfrac {9}{4}\).
            • 5.

              已知正实数\(x\),\(y\)满足\(x+y+3=xy\),若对任意满足条件的\(x\),\(y\),都有\({{(x+y)}^{2}}-a(x+y)+1\geqslant 0\)恒成立,则实数\({a}\)的取值范围为________

            • 6.
              已知点\(A\)在线段\(BC\)上\((\)不含端点\()\),\(O\)是直线\(BC\)外一点,且\( \overrightarrow{OA}-2a \overrightarrow{OB}-b \overrightarrow{OC}= \overrightarrow{0}\),则\( \dfrac {a}{a+2b}+ \dfrac {2b}{1+b}\)的最小值是 ______ .
            • 7.

              设函数\(f\left( x \right)={\ln }x\),若\(a,b\)是两个不相等的正数且\(p=f\left( \sqrt{ab} \right),q=f\left( \dfrac{a+b}{2} \right)\) \(r=\dfrac{1}{2}f\left( \dfrac{{{a}^{2}}+{{b}^{2}}}{2} \right)\) \(v=\dfrac{1}{2}\left[ f\left( a \right)+f\left( b \right) \right]\),则下列关系式中正确的是\((\)    \()\)

              A.\(p=q < v < r\)
              B.\(p=v < q < r\)
              C.\(p=v < r < q\)
              D.\(p < v < q < r\)
            • 8.

              设函数\(f\left( x \right)={{x}^{2}}+aIn\left( 1+x \right)\)有两个极值点\(x_{1}\),\(x_{2}\),且\({{x}_{1}} < {{x}_{2}}\)

              \((I)\)求\(a\)的取值范围,并讨论\(f\left( x \right)\)的单调性;

              \((II)\)证明:\(f\left( {{x}_{2}} \right) > \dfrac{1-2In2}{4}\)

            • 9.
              已知\(a\),\(b\),\(c\),\(d\)为实数,且\(a^{2}+b^{2}=4\),\(c^{2}+d^{2}=16\),证明\(ac+bd\leqslant 8\).
            • 10. 已知函数\(y=x+ \dfrac {2}{x-1}\),\(x∈(1,+∞)\),则\(y\)的最小值是______
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