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            • 1.
              \({{S}_{n}}\) 为数列\(\{{{a}_{n}}\}\) 的前\(n\) 项和\(.\)已知\({{a}_{n}} > 0\) \({{a}_{n}}^{2}+3{{a}_{n}}=6{{S}_{n}}+4\)
              \((1)\)求\(\{{{a}_{n}}\}\) 的通项公式;

              \((2)\)设\({{b}_{n}}=\dfrac{3}{{{a}_{n}}{{a}_{n+1}}}\),求数列\(\{{{b}_{n}}\}\)的前\(n\)项和\({{T}_{n}}\)

            • 2.

              设数列\(\left\{ {{a}_{n}} \right\}\)\(n\)项和为\({{s}_{n}}\),且\({{s}_{n}}=2{{a}_{n}}-2(n\in {{N}^{*}})\)

              \((\)Ⅰ\()\)证明:数列\(\left\{ {{a}_{n}} \right\}\)是等比数列,并求出其通项公式;

              \((\)Ⅱ\()\)证明:数列\(\left\{ {{a}_{n}} \right\}\)中不可能存在三项成等差.

            • 3.

              已知\(\{a_{n}\}\)是等比数列,\(a_{1}=1\),\(a_{4}=8\),\(\{b_{n}\}\)是等差数列,\(b_{1}=3\),\(b_{4}=12\),

                  \((1)\)求\(\{a_{n}\}\)和\(\{b_{n}\}\)的通项公式;

                  \((2)\)设\(c_{n}=a_{n}+b_{n}\),求数列\(\{c_{n}\}\)的前\(n\)项和\(S_{n}\).

            • 4.

              已知等差数列\(\left\{ {{a}_{n}} \right\}\)的前\(n\)项和\({{S}_{n}}\),满足\({{S}_{3}}=0,{{S}_{5}}=-5\),则数列\(\left\{ \dfrac{1}{{{a}_{2n-1}}{{a}_{2n+1}}} \right\}\)的前\(50\)项和\({{T}_{50}}=\) __________.

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