8.
已知数列\(\{b_{n}\}\)是首项为\(2\)且公比为\(q\)的等比数列,数列\(\{a_{n}\}\)满足\(a_{1}=3q\),\(a_{n+1}-qb_{n+1}=a_{n}-qb_{n}(n∈N^{*}).\)
\((1)\)求数列\(\{a_{n}\}\)的通项公式;
\((2)\)若\(q= \dfrac{1}{2} \),数列\(\{b_{n}\}\)前\(n\)项和为\(S_{n}\),求所有满足等式\( \dfrac{{S}_{n}-m}{{S}_{n+1}-m}= \dfrac{1}{{b}_{m}+1} \)成立的正整数\(m\),\(n\);
\((3)\)若\(q < 0\),且对任意\(m\),\(n∈N^{*}\),都有\( \dfrac{{a}_{m}}{{a}_{n}}∈\left( \dfrac{1}{6},6\right) \),求实数\(q\)的取值范围.