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            • 1.

              在数列\(\left\{ {{a}_{n}} \right\}\)中,\({{a}_{{1}}}{+2}{{a}_{2}}+{{2}^{2}}{{a}_{3}}+\cdots +{{2}^{n-1}}{{a}_{n}}=(n\cdot {{2}^{n}}-{{2}^{n}}+1)\ t\)对任意\(n\in {{N}^{*}}\)成立,其中常数\(t > 0.\)若关于\(n\)的不等式\(\dfrac{1}{{{a}_{2}}}+\dfrac{1}{{{a}_{4}}}+\dfrac{1}{{{a}_{8}}}+\cdots +\dfrac{1}{{{a}_{{{2}^{n}}}}} > \dfrac{m}{{{a}_{1}}}\)的解集为\(\{n|n\geqslant 4,n\in {{N}^{*}}\}\),则实数\(m\)的取值范围是                   

            • 2.

              已知数列\(\{a_{n}\}\)的首项\(a_{1}=1\),前\(n\)项的和为\(S_{n}\),且满足\(2a_{n+1}+S_{n}=2(n∈N^{*})\),则满足\(\dfrac{1\mathrm{\ }001}{1\mathrm{\ }000} < \dfrac{S_{2n}}{S_{n}} < \dfrac{11}{10}\)的\(n\)的最大值为              \(.\) 

            • 3. 已知数列\(\{{{a}_{n}}\}\)的前\(n\)项和为\({{S}_{n}}\),若\(3{{S}_{n}}=2{{a}_{n}}-3n\),则\({{a}_{2018}}=\)

              A.\({{2}^{2018}}-1\)
              B.\({{3}^{2018}}-6\)
              C.\({{\left( \dfrac{1}{2} \right)}^{2018}}-\dfrac{7}{2}\)
              D.\({{\left( \dfrac{1}{3} \right)}^{2018}}-\dfrac{10}{3}\) 
            • 4.

              已知数列\(\left\{ {{a}_{n}} \right\}\)的前\(n\)项的和\(S_{n}\),满足\(\dfrac{3}{2}{{a}_{n}}={{S}_{n}}+2+{{(-1)}^{n}}(n\in {{N}^{*}})\) .

              \((1)\)求数列\(\left\{ {{a}_{n}} \right\}\)的通项公式.

              \((2)\)设\({T}_{n}= \dfrac{1}{{a}_{1}}+ \dfrac{1}{{a}_{2}}+ \dfrac{1}{{a}_{3}}+⋯+ \dfrac{1}{{a}_{n}} \) ,是否存在正整数\(k\),使得当\(n\geqslant 3\)时,\({{T}_{n}}\in \left( \dfrac{k}{10},\dfrac{k+1}{10} \right)\) 如果存在,求出\(k\);如果不存在,请说明理由\(.\) 

            • 5. 数列\(\{a_{n}\}\)满足\(a_{1}=1\),\( \dfrac {1}{2a_{n+1}}= \dfrac {1}{2a_{n}}+1(n∈N^{*}).\)
              \((\)Ⅰ\()\)求证\(\{ \dfrac {1}{a_{n}}\}\)是等差数列;
              \((\)Ⅱ\()\)若\(b_{n}=a_{n}⋅a_{n+1}\),求\(\{b_{n}\}\)的前\(n\)项和\(S_{n}\).
            • 6.

              在数列\(\{{{a}_{n}}\}\)中,\({{a}_{1}}=4,{{a}_{n+1}}-1=3({{a}_{n}}-1)\) ,则数列\(\left\{ {{a}_{n}} \right\}\)的通项公式\({{a}_{n}}=\) ______.

            • 7. 若数列\(\{a_{n}\}\)满足\(a_{n}-(-1)^{n}a_{n-1}=n(n\geqslant 2)\),\(S_{n}\)是\(\{a_{n}\}\)的前\(n\)项和,则\(S_{40}=\)________.
            • 8. 若数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),且满足\(a_{n}+2S_{n}S_{n-1}=0(n\geqslant 2)\),\(a_{1}= \dfrac{1}{2}\).
              \((1)\)求证:\(\left\{ \left. \dfrac{1}{S_{n}} \right. \right\}\)成等差数列;

              \((2)\)求数列\(\{a\)\({\,\!}_{n}\)\(\}\)的通项公式.

            • 9.

              单调递增数列\(\left\{ {{a}_{n}} \right\}\)的前\(n\)项和为\({{S}_{n}}\),且满足\(4{{S}_{n}}=a_{n}^{2}+4n\).

              \((1)\)求数列\(\left\{ {{a}_{n}} \right\}\)的通项公式;    
              \((2)\)令\({{b}_{n}}=\dfrac{{{a}_{n}}}{{{2}^{n}}}\),求数列\(\left\{ {{b}_{n}} \right\}\)的前\(n\)项和\({{T}_{n}}\).
            • 10. 若数列\(\{a_{n}\}\)满足条件:存在正整数\(k\),使得\(a_{n+k}+a_{n-k}=2a_{n}\)对一切\(n∈N^{*}\),\(n > k\)都成立,则称数列\(\{a_{n}\}\)为\(k\)级等差数列.
              \((1)\)已知数列\(\{a_{n}\}\)为\(2\)级等差数列,且前四项分别为\(2\),\(0\),\(4\),\(3\),求\(a_{8}+a_{9}\)的值;
              \((2)\)若\(a_{n}=2n+\sin ωn(ω\)为常数\()\),且\(\{a_{n}\}\)是\(3\)级等差数列,求\(ω\)所有可能值的集合,并求\(ω\)取最小正值时数列\(\{a_{n}\}\)的前\(3n\)项和\(S_{3n}\);
              \((3)\)若\(\{a_{n}\}\)既是\(2\)级等差数列\(\{a_{n}\}\),也是\(3\)级等差数列,证明:\(\{a_{n}\}\)是等差数列.
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