优优班--学霸训练营 > 知识点挑题
全部资源
          排序:
          最新 浏览

          50条信息

            • 1.

              设\(-3\pi < \alpha < -\dfrac{5\pi }{2}\),化简\(\sqrt{\dfrac{1+\cos (\alpha -2018\pi )}{2}}\)的结果是

              A.\(\sin \dfrac{\alpha }{2}\)
              B.\(-\sin \dfrac{\alpha }{2}\)
              C.\(\cos \dfrac{\alpha }{2}\)
              D.\(-\cos \dfrac{\alpha }{2}\)
            • 2.
              已知\(f(α)= \dfrac {\sin ( \dfrac {π}{2}+α)\cdot \sin (2π-α)}{\cos (-\pi -\alpha )\cdot \sin ( \dfrac {3}{2}\pi +\alpha )}\).
              \((1)\)若\(α\)是第三象限角,且\(\cos (α- \dfrac {3}{2}π)= \dfrac {1}{5}\),求\(f(α)\)的值;
              \((2)\)若\(f(α)=-2\),求\(2\sin α\cos α+\cos ^{2}α\)的值.
            • 3.
              已知\( \overrightarrow{a}=(1-\cos x,2\sin \dfrac {x}{2}), \overrightarrow{b}=(1+\cos x,2\cos \dfrac {x}{2})\)
              \((1)\)若\(f(x)=2+\sin x- \dfrac {1}{4}| \overrightarrow{a}- \overrightarrow{b}|^{2}\),求\(f(x)\)的表达式.
              \((2)\)若函数\(f(x)\)和函数\(g(x)\)的图象关于原点对称,求\(g(x)\)的解析式.
              \((3)\)若\(h(x)=g(x)-λf(x)+1\)在\([- \dfrac {π}{2}, \dfrac {π}{2}]\)上是增函数,求实数\(λ\)的取值范围.
            • 4.
              定义行列式运算:\( \begin{vmatrix} a_{1} & a_{2} \\ a_{3} & a_{4}\end{vmatrix} =a_{1}a_{4}-a_{2}a_{3}\),若将函数\(f(x)= \begin{vmatrix} \sin x & \cos x \\ 1 & \sqrt {3}\end{vmatrix} \)的图象向右平移\(φ(φ > 0)\)个单位后,所得图象对应的函数为奇函数,则\(m\)的最小值是\((\)  \()\)
              A.\( \dfrac {π}{6}\)
              B.\( \dfrac {π}{3}\)
              C.\( \dfrac {2π}{3}\)
              D.\( \dfrac {5π}{6}\)
            • 5.
              \((1)\)化简\(f(α)= \dfrac {\sin ( \dfrac {π}{2}+α)+\sin (-π-α)}{3\cos (2\pi -\alpha )+\cos ( \dfrac {3π}{2}-\alpha )}\); 
              \((2)\)若\(\tan α=1\),求\(f(α)\)的值.
            • 6.
              已知\(\cos ( \dfrac {π}{6}-θ)= \dfrac {2 \sqrt {2}}{3}\),则\(\cos ( \dfrac {π}{3}+θ)=\) ______ .
            • 7.

              已知\(f\left( \alpha \right)=\dfrac{\cos \left( \dfrac{\pi }{2}+\alpha \right)\cdot \cos \left( 2\pi -\alpha \right)\cdot \sin \left( -\alpha +\dfrac{3}{2}\pi \right)}{\sin \left( -\pi -\alpha \right)\sin \left( \dfrac{3}{2}\pi +\alpha \right)}\) .

              \((1)\)化简\(f\left( \alpha \right)\);\((2)\)若\(\alpha \)是第三象限角,且\(\cos \left( \alpha -\dfrac{3}{2}\pi \right)=\dfrac{1}{5}\),求\(f\left( \alpha \right)\)的值.

            • 8.

              已知\(\sin \alpha +2\cos \alpha =\dfrac{\sqrt{10}}{2}\),则\(\tan 2α=\)

              A.\(\dfrac{4}{3}\)
              B.\(\dfrac{3}{4}\)
              C.\(-\dfrac{3}{4}\)
              D.\(-\dfrac{4}{3}\)
            • 9.

              如图,以\(Ox\)为始边作角\(α\)\(β\)\((0 < \)\(β\)\( < \)\(α\)\( < π)\),它们终边分别与单位圆相交于点\(P\)\(Q\),已知点\(P\)的坐标为\(\left(\begin{matrix}- \dfrac{3}{5}, \dfrac{4}{5}\end{matrix}\right)\).

              \((1)\)求\( \dfrac{\sin 2α+\cos 2α+1}{1+\tan α}\)的值;

              \((2)\)若\(∠POQ=90^{\circ}\),求\(\sin (\)\(α\)\(+\)\(β\)\().\)

            • 10.

              计算\(\dfrac{\cos {{10}^{0}}-\sqrt{3}\cos (-{{100}^{0}})}{\sqrt{1-\sin {{10}^{0}}}}=\)          \(.(\)用数字做答\()\)

            0/40

            进入组卷