优优班--学霸训练营 > 知识点挑题
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            • 1.
              已知\(\cos (α+ \dfrac {2}{3}π)= \dfrac {4}{5},- \dfrac {π}{2} < α < 0\),则\(\sin (α+ \dfrac {π}{3})+\sin α\)等于\((\)  \()\)
              A.\(- \dfrac {4 \sqrt {3}}{5}\)
              B.\(- \dfrac {3 \sqrt {3}}{5}\)
              C.\( \dfrac {3 \sqrt {3}}{5}\)
              D.\( \dfrac {4 \sqrt {3}}{5}\)
            • 2.
              已知向量\( \overrightarrow{a}=(\cos \dfrac {3x}{2},\sin \dfrac {3x}{2})\),\( \overrightarrow{b}=(\cos \dfrac {x}{2},-\sin \dfrac {x}{2})\),函数\(f(x)= \overrightarrow{a}⋅ \overrightarrow{b}-m| \overrightarrow{a}+ \overrightarrow{b}|+1\),\(x∈[- \dfrac {π}{3}, \dfrac {π}{4}]\),\(m∈R\).
              \((1)\)当\(m=0\)时,求\(f( \dfrac {π}{6})\)的值;
              \((2)\)若\(f(x)\)的最小值为\(-1\),求实数\(m\)的值;
              \((3)\)是否存在实数\(m\),使函数\(g(x)=f(x)+ \dfrac {24}{49}m^{2}\),\(x∈[- \dfrac {π}{3}, \dfrac {π}{4}]\)有四个不同的零点?若存在,求出\(m\)的取值范围;若不存在,说明理由.
            • 3.
              已知\(α\)为第三象限角,\(f(α)= \dfrac {\sin (α- \dfrac {π}{2})\cos ( \dfrac {3π}{2}+α)\tan (π-α)}{\tan (-α-π)\sin (-α-π)}\).
              \((1)\)化简\(f(α)\);
              \((2)\)若\(\cos (α- \dfrac {3π}{2})= \dfrac {1}{5}\),求\(f(α)\)的值.
            • 4.
              已知函数\(f(x)=A\sin (ωx+φ)(A > 0,ω,0,|φ| < π)\),在同一周期内,当\(x= \dfrac {π}{12}\)时,\(f(x)\)取得最大值\(3\);当\(x= \dfrac {7}{12}π\)时,\(f(x)\)取得最小值\(-3\).
              \((\)Ⅰ\()\)求函数\(f(x)\)的解析式;
              \((\)Ⅱ\()\)若\(x∈[- \dfrac {π}{3}, \dfrac {π}{6}]\)时,函数\(h(x)=2f(x)+1-m\)有两个零点,求实数\(m\)的取值范围.
            • 5.
              已知函数\(f(x)= \sqrt {3}\sin 2x-2\cos ^{2}x\).
              \((1)\)求\(f( \dfrac {π}{6})\)的值;
              \((2)\)求\(f(x)\)的单调递增区间.
            • 6.
              已知\(\triangle ABC\),角\(A\),\(B\),\(C\)的对边分别是\(a\),\(b\),\(c\),向量\( \overrightarrow{m}=(a,-2b-c)\),\( \overrightarrow{n}=(\cos A,\cos C)\),且\( \overrightarrow{m}/\!/ \overrightarrow{n}\).
              \((I)\)求角\(A\)的大小;
              \((II)\)求\(2 \sqrt {3}\cos ^{2} \dfrac {C}{2}-\sin (B- \dfrac {π}{3})\)的最大值,并求取得最大值时角\(B\),\(C\)的大小.
            • 7.
              函数\(f(x)=\sin x- \sqrt {3}\cos x(x∈[-π,0])\)的递增区间是\((\)  \()\)
              A.\([-π,- \dfrac {5π}{6}]\)
              B.\([- \dfrac {5π}{6},- \dfrac {π}{6}]\)
              C.\([- \dfrac {π}{3},0]\)
              D.\([- \dfrac {π}{6},0]\)
            • 8.
              \(\sin 50^{0}(1+ \sqrt {3}\tan 10^{0})\)的值 ______ .
            • 9.
              已知函数\(f(x)=4\tan x\sin ( \dfrac {π}{2}-x)\cos (x- \dfrac {π}{3})- \sqrt {3}\).
              \((1)\)求\(f(x)\)的定义域与最小正周期;
              \((2)\)讨论\(f(x)\)在区间\([- \dfrac {π}{4}, \dfrac {π}{4}]\)上的单调性.
            • 10.
              在\(\triangle ABC\)中,角\(A\),\(B\),\(C\)的对边分别为\(a\),\(b\),\(c\),且\( \dfrac {\cos B-2\cos A}{2a-b}= \dfrac {\cos C}{c}\).
              \((1)\)求\( \dfrac {a}{b}\)的值;
              \((2)\)若角\(A\)是钝角,且\(c=3\),求\(b\)的取值范围.
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