共50条信息
给出下列判断
\(①\)若存在\(x_{1}\),\(x_{2}∈I\),当\(x_{1} < x_{2}\)时,\(f(x_{1}) < f(x_{2})\)则\(y=f(x)\)在\(I\)上是增函数;
\(②y=\dfrac{1}{x}\)在定义域内为减函数;
\(③y=(x-1)^{2}\)在\((0,+∞)\)上是增函数;
\(④y=-\dfrac{1}{x}\)在\((-∞,0)\)上为增函数;
其中错误的个数有\((\) \()\)
进入组卷