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            • 1.

              已知\(a=\dfrac{1}{\pi }\underset{2}{\overset{-2}{\int}}\,\left( \sqrt{4-{{x}^{2}}}+{\sin }x \right)dx\),则二项式\({{\left( \dfrac{x}{2}-\dfrac{a}{{{x}^{2}}} \right)}^{9}}\)的展开式中的常数项为                        \((\)   \()\)

              A.\(-\dfrac{15}{8}\)
              B.\(-\dfrac{21}{2}\)
              C.\(-\dfrac{5}{4}\)
              D.\(-1\)
            • 2.

              如图,设点\(P\)从原点沿曲线\(y=x\)\({\,\!}^{2}\)向点\(A(2,4)\)移动,直线\(OP\)与曲线\(y=x\)\({\,\!}^{2}\)围成图形的面积为\(S\)\({\,\!}_{1}\),直线\(OP\)与曲线\(y=x\)\({\,\!}^{2}\)及直线\(x=2\)围成图形的面积为\(S\)\({\,\!}_{2}\),若\(S\)\({\,\!}_{1}\)\(=S\)\({\,\!}_{2}\),求点\(P\)的坐标.

            • 3. 如图所示的阴影部分是由\(x\)轴及曲线\(y={\sin }x\)围成,在矩形区域\(OABC\)内随机取一点,则该点取自阴影部分的概率是_____________

            • 4.

              已知等差数列\(\{a_{n}\}\)中,\(a_{5}+a_{7}=\int _{0}^{π}\sin xdx \),则\(a_{4}+a_{6}+a_{8}=(\)  \()\)


              A.\(3\)                               
              B.\(4\)                                
              C.\(5\)           
              D.\(6\)
            • 5.

              若\({{\left( {{x}^{{2}}}-\dfrac{{1}}{ax} \right)}^{{9}}}(a\in R)\)展开式中\(x^{9}\)的系数是\(-\dfrac{{21}}{{2}}\),则\(\int_{0}^{a}{\sin xdx}\)等于  \((\)    \()\)

              A.\(1-\cos 2\)
              B.\(2-\cos 1\)
              C.\(\cos 2-1\)
              D.\(1+\cos 2\)
            • 6.

              \(F(x)=\int _{0}^{x}({t}^{2}+2t-8)dt (x > 0)\).

              \((1)\)求\(F(x)\)的单调区间.

              \((2)\)求函数\(F(x)\)在\([1,3]\)上的最值.

            • 7.

              \(∫_{0}^{2}\left(3{x}^{2}+k\right)dx=10,则k= \) ________\(.\)  

            • 8.

              已知\(m=3\int_{0}^{\pi }{\sin xdx}\),则二项式\({{(a+2b-3c)}^{m}}\)的展开式中\(a{{b}^{2}}{{c}^{m-3}}\)的系数为________.

            • 9.

              若\(a{=}\int_{\frac{\pi}{2}}^{2}\sin{xdx}{,}b{=}\int_{0}^{1}\cos{xdx}\),则\(a\)与\(b\)的关系是\(({  })\)

              A.\(a{+}b{=}0\)
              B.\(a{ > }b\)
              C.\(a{ < }b\)
              D.\(a{=}b\)
            • 10.

              计算\(\int_{-1}^{1}{(\sqrt{1-{{x}^{2}}}+{{e}^{|x|}})}dx=\)______________.

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