共50条信息
\(i\)为虚数单位，\(i^{2018}=\)________．
计算：\( \dfrac{2+2i}{(1-i)^{2}}·\left( \left. \dfrac{ \sqrt{2}}{1+i} \right. \right)^{2 020} =\)________．
已知\(i\)是虚数单位，则\({{\left( \dfrac{1-i}{1+i} \right)}^{6}}+{{\left( \dfrac{\sqrt{2}}{1-i} \right)}^{2018}}=\)____________________\(.\)
\( \dfrac{-2 \sqrt{3}+i}{1+2 \sqrt{3}i}+\left( \left. \dfrac{ \sqrt{2}}{1-i} \right. \right)^{2 017} =\)________．
已知复数\(z=i+i^{2}+i^{3}+…+i^{2019}\)，则\(z=\)________．
设\(f(n)={\left( \dfrac{1+i}{1-i}\right)}^{n}+{\left( \dfrac{1-i}{1+i}\right)}^{n}\left(n∈N\right) \)，则集合\(\left\{x \left|x=f(n) \right.\right\} \)的子集个数是 ．
\(\left( \left. \dfrac{1+i}{1-i} \right. \right)^{2 018} =\)________．
复数\({{\left( \dfrac{1-i}{1+i} \right)}^{10}}\)的值是____________．
\(\left( \left. \dfrac{1+i}{1-i} \right. \right)^{6} + \dfrac{ \sqrt{2}+ \sqrt{3}i}{ \sqrt{3}- \sqrt{2}i}=\)_______．
复数\(z=a(1+i)-2(i\)为虚数单位\()\)为纯虚数，则\(a=\)________；\(|z|=3\)表示的图形是_______________________．
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