共50条信息
已知复数\(z=x+yi(x z=x+yi(x\)、\(y∈ R)\),且有\( \dfrac{x}{1-i}=1+yi \),则\(\left|z\right|= \)
已知复数\({z}_{1}=\left(2x+1\right)+2i,{z}_{2}=-x-yi\left(x,y∈R\right) \)
\((2)\)若复数\(\left(1+i\right)·{z}_{1} \)为纯虚数,求复数\({{z}_{1}}\)的模\(\left| {{z}_{1}} \right|\)。
若\(x\)是纯虚数,\(y\)是实数,且\(2x-1+i=y-(3-y)i\),则\(x+y\)等于( )
若\( \dfrac{1-i}{1+i}=a+bi,(a,b∈R) \),则\( \dfrac{a}{b} \)的值是 \((\) \()\)
满足\(z+\dfrac{10}{z}\)是实数,且\(z+4\)的实部与虚部相等的虚数\(z\)是否存在\(?\)若存在,求出虚数\(z\);若不存在,请说明理由.
已知\(=2-2\)\(i\)\((\)\(i\)为虚数单位\()\),则实数\(b\)\(=\)( )
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