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            • 1.

              已知\(\{b_{n}\}\)为等比数列,\(b_{5}=2\),则\(b_{1}·b_{2}·…·b_{9}=2^{9}\),若\(\{a_{n}\}\)为等差数列,\(a_{5}=2\),则类似结论为  \((\)    \()\)

              A.\(a_{1}·a_{2}·…·a_{9}=2^{9}\)
              B.\(a_{1}+a_{2}+…+a_{9}=2^{9}\)
              C.\(a_{1}·a_{2}·…·a_{9}=2×9\)
              D.\(a_{1}+a_{2}+…+a_{9}=2×9\)
            • 2.

              在以下的类比推理中结论正确的是 (    )

              A.“若\(a\cdot 3=b\cdot 3\),则\(a=b\)”类比推出“若\(a\cdot 0=b\cdot 0\),则\(a=b\)”

              B.“若\((a+b)c=ac+bc\)”类比推出“\((a\cdot b)c=ac\cdot bc\)”

              C.“若\((a+b)c=ac+bc\)” 类比推出“\(\dfrac{a+b}{c}=\dfrac{a}{c}+\dfrac{b}{c}\)  \((c\neq 0)\)”

              D.“\((ab{)}^{n}={a}^{n}{b}^{n} \)” 类比推出“\((a+b{)}^{n}={a}^{n}+{b}^{n} \)”
            • 3.

              给出下列三个类比结论:

              \(①(ab)^{n}=a^{n}b^{n}\)与\((a+b)^{n}\)类比,则有\((a+b)^{n}=a^{n}+b^{n}\);

              \(②\log _{a}(xy)=\log _{a}x+\log _{a}y\)与\(\sin (α+β)\)类比,则有\(\sin (α+β)=\sin α\sin β\);

              \(③(a+b)^{2}=a^{2}+2ab+b^{2}\)与\((a+b)^{2}\)类比,则有\((a+b)^{2}=a^{2}+2a·b+b^{2}\).

              其中结论正确的个数是  \((\)    \()\)

              A.\(0\)
              B.\(1\)
              C.\(2\)
              D.\(3\)
            • 4.

              定义\(A*B\),\(B*C\),\(C*D\),\(D*A\)的运算分别对应下面图中的\(⑴\),\(⑵\),\(⑶\),\(⑷\),则图中\(⑸\),\(⑹\)对应的运算是(    )

              A.\(B*D\),\(A*D\)
              B.\(B*D\),\(A*C\)
              C.\(B*C\),\(A*D\)
              D.\(C*D\),\(A*D\)
            • 5.

              已知\(f\left( x+1 \right)=\dfrac{2f\left( x \right)}{f\left( x \right)+2}\),\(f\left( 1 \right)=1(x\in N*)\),猜想\(f\left( x \right)\)的表达式为\((\)   \()\)

              A.\(f\left( x \right)=\dfrac{2}{x+1}\)
              B.\(f\left( x \right)=\dfrac{4}{{{2}^{x}}+2}\)
              C.\(f\left( x \right)=\dfrac{1}{x+1}\)
              D.\(f\left( x \right)=\dfrac{2}{2x+1}\)
            • 6.

              已知点\(A\left({x}_{1},x_{1}^{2}\right) \),\(B\left({x}_{2},x_{2}^{2}\right) \)是函数\(y=x^{2}\)图象上任意不同的两点,依据图象知,线段\(AB\)总是位于\(A\),\(B\)两点之间函数图象的上方,因此有结论\(\dfrac{x_{1}^{2}+x_{2}^{2}}{{2}} > {{\left( \dfrac{{{x}_{{1}}}+{{x}_{{2}}}}{{2}} \right)}^{{2}}}\)成立,运用类比方法可知,若点\(A(x_{1},\sin x_{1})\),\(B(x_{2},\sin x_{2})\)是函数\(y=\sin x(x∈(0,π))\)图象上不同的两点,则类似地有结论  \((\)    \()\)

              A.\(\dfrac{\sin {{x}_{1}}+\sin {{x}_{2}}}{2} > \sin \dfrac{{{x}_{1}}+{{x}_{2}}}{2}\)
              B.\(\dfrac{\sin {{x}_{1}}+\sin {{x}_{2}}}{2} < \sin \dfrac{{{x}_{1}}+{{x}_{2}}}{2}\)
              C.\(\dfrac{\sin {{x}_{1}}+\sin {{x}_{2}}}{2}\geqslant \sin \dfrac{{{x}_{1}}+{{x}_{2}}}{2}\)
              D.\(\dfrac{\sin {{x}_{1}}+\sin {{x}_{2}}}{2}\leqslant \sin \dfrac{{{x}_{1}}+{{x}_{2}}}{2}\)
            • 7.

              设\(⊕ \)是\(R\)内的一个运算,\(A\)是\(R\)的非空子集\(.\)若对于任意\(a\),\(b∈A\),有\(a⊕ b∈A\),则称\(A\)对运算\(⊕ \)封闭\(.\)下列数集对加法、减法、乘法和除法\((\)除数不等于零\()\)四则运算都封闭的是 (    )


              A.自然数集
              B.整数集
              C.有理数集
              D.无理数集
            • 8.

              已知三角形的三边分别为\(a\),\(b\),\(c\),内切圆的半径为\(r\),则三角形的面积为\(s=\dfrac{1}{2}(a+b+c)r.\)已知四面体的四个面的面积分别为\(S_{1}\),\(S_{2}\),\(S_{3}\),\(S_{4}\),内切球的半径为\(R.\)类比三角形的面积可得四面体的体积为

              A.\(V=\dfrac{1}{2}({{S}_{1}}+{{S}_{2}}+{{S}_{3}}+{{S}_{4}})R\)
              B.\(V=\dfrac{1}{3}({{S}_{1}}+{{S}_{2}}+{{S}_{3}}+{{S}_{4}})R\)
              C.\(V=\dfrac{1}{4}({{S}_{1}}+{{S}_{2}}+{{S}_{3}}+{{S}_{4}})R\)
              D.\(V=(S_{1}+S_{2}+S_{3}+S_{4})R\)
            • 9.
              对于任意的两个实数对\((a,b)\)和\((c,d)\),规定:\((a,b)=(c,d)\),当且仅当\(a=c\),\(b=d\);运算“\(⊗\)”为:\((a,b)⊗(c,d)=(ac-bd,bc+ad)\);运算“\(⊕\)”为:\((a,b)⊕(c,d)=(a+c,b+d)\),设\(p\),\(q∈R\),若\((1,2)⊗(p,q)=(5,0)\),则\((1,2)⊕(p,q)=(\)  \()\)
              A.\((4,0)\)
              B.\((2,0)\)
              C.\((0,2)\)
              D.\((0,-4)\)
            • 10.
              如图所示,是某小朋友在用火柴拼图时呈现的图形,其中第\(1\)个图形用了\(3\)根火柴,第\(2\)个图形用了\(9\)根火柴,第\(3\)个图形用了\(18\)个火柴,\(…\),第\(2014\)个图形用的火柴根数为\((\)  \()\)
              A.\(2012×2015\)
              B.\(2013×2014\)
              C.\(2013×2015\)
              D.\(3021×2015\)
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