优优班--学霸训练营 > 知识点挑题
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            • 1.

              已知\(A\)、\(B\)、\(C\)为\(\triangle ABC\)的三个内角,向量\(m\)满足\(|m|=\dfrac{\sqrt{6}}{2}\),且\(m=(\sqrt{2}\sin \dfrac{B+C}{2},\cos \dfrac{B-C}{2})\),若\(A\)最大时,动点\(P\)使得\(|\overrightarrow{PB}|\)、\(|\overrightarrow{BC}|\)、\(|\overrightarrow{PC}|\)成等差数列,则\(\dfrac{|\overrightarrow{PA}|}{|\overrightarrow{BC}|}\)的最大值是

              A.\(\dfrac{2\sqrt{3}}{3}\)
              B.\(\dfrac{2\sqrt{2}}{3}\)
              C.\(\dfrac{\sqrt{2}}{4}\)
              D.\(\dfrac{3\sqrt{2}}{4}\)
            • 2.

              满足条件\(|z-2i|+|z+1|= \sqrt{5}\)的点的轨迹是\((\)  \()\)

              A.椭圆 
              B.直线
              C.线段 
              D.圆
            • 3.

              已知圆\({{F}_{1}}\):\({{\left( x+2 \right)}^{2}}+{{y}^{2}}=36\),定点\({{F}_{2}}\left( 2,0 \right)\),\(A\)是圆\({{F}_{1}}\)上的一动点,线段\({{F}_{2}}A\) 的垂直平分线交半径\({{F}_{1}}A\)\(P\)点,则\(P\)点的轨迹\(C\)的方程是\((\)   \()\)

              A.\(\dfrac{{{x}^{2}}}{4}+\dfrac{{{y}^{2}}}{3}=1\)
              B.\(\dfrac{{{x}^{2}}}{9}+\dfrac{{{y}^{2}}}{5}=1\)
              C.\(\dfrac{{{x}^{2}}}{3}+\dfrac{{{y}^{2}}}{4}=1\)
              D.\(\dfrac{{{x}^{2}}}{5}+\dfrac{{{y}^{2}}}{9}=1\)
            • 4.
              如果命题“曲线\(C\)上的点的坐标都是方程\(f(x,y)=0\)的解”是正确的,则下列命题中正确的是\((\)  \()\)
              A.曲线\(C\)是方程\(f(x,y)=0\)的曲线
              B.方程\(f(x,y)=0\)的每一组解对应的点都在曲线\(C\)上
              C.不满足方程\(f(x,y)=0\)的点\((x,y)\)不在曲线\(C\)上
              D.方程\(f(x,y)=0\)是曲线\(C\)的方程
            • 5.

              已知\(k∈R\),直线\(l_{1}\):\(x+ky=0\)过定点\(P\),直线\(l_{2}\):\(kx-y-2k+2=0\)过定点\(Q\),两直线交于点\(M\),则\(|MP|+|MQ|\)的最大值是\((\)   \()\)

              A.\(2\sqrt{2}\)
              B.\(4\)
              C.\(4\sqrt{2}\)
              D.\(8\)
            • 6.

              当\(m\)变化时,抛物线\(y-4x-4my=0\)的顶点\(M\)的轨迹方程是\((\)   \()\)

              A.\(x^{2}=4y\)
              B.\(x^{2}=-4y\)
              C.\(y^{2}=4x\)
              D.\(y^{2}=-4x\)
            • 7.

              已知\(A,B,C\)为\(\Delta ABC\)的三个内角,向量\(\overrightarrow{m}\)满足\(|\overrightarrow{m}|=\dfrac{\sqrt{6}}{2}\),且\(\overrightarrow{m}=(\sqrt{2}\sin \dfrac{B+C}{2},\cos \dfrac{B-C}{2})\),若\(A\)最大时,动点\(P\)使得\(||\overrightarrow{PB}|,|\overrightarrow{BC}|,|\overrightarrow{PC}|\)成等差数列,则\(\dfrac{\overrightarrow{|PA|}}{\overrightarrow{|BC|}}\)的最大值是\((\)      \()\)

              A.\(\dfrac{2\sqrt{3}}{3}\)
              B.\(\dfrac{2\sqrt{2}}{3}\)
              C.\(\dfrac{\sqrt{2}}{4}\)
              D.\(\dfrac{3\sqrt{2}}{4}\)
            • 8.
              已知\(|\overset{—→}{AB}|=3\),点 \(A\)\(B\)分别在 \(y\)轴和 \(x\)轴上运动, \(O\)为原点,\(\overset{—→}{OP}= \dfrac{1}{3}\overset{—→}{OA}+ \dfrac{2}{3}\overset{—→}{OB}\),则动点 \(P\)的轨迹方程是(    )
              A.\( \dfrac{x^{2}}{4}+\) \(y\)\({\,\!}^{2}=1\)                        
              B.\(x\)\({\,\!}^{2}+ \dfrac{y^{2}}{4}=1\)
              C.\( \dfrac{x^{2}}{9}+\) \(y\)\({\,\!}^{2}=1\)                        
              D.\(x\)\({\,\!}^{2}+ \dfrac{y^{2}}{9}=1\)
            • 9.

              已知动圆\(P\)与定圆\(C\):\((x+2)^{2}+y^{2}=1\)相外切,又与定直线\(L\):\(x=1\)相切,那么动圆的圆心\(P\)的轨迹方程是\((\)   \()\)

              A.\(y^{2}=-8x\)
              B.\(x^{2}=-8y\)
              C.\(x^{2}-y^{2}=1\)
              D.\({{x}^{2}}+\dfrac{{{y}^{2}}}{2}=1\)
            • 10.

              若动点\(M(x,y)\)满足\(\sqrt{{{(x-2)}^{2}}+{{y}^{2}}}=\dfrac{|x+y-2|}{\sqrt{2}}\),则\(M\)的轨迹为\((\)  \()\)


              A.椭圆        
              B.双曲线      
              C.抛物线      
              D.直线
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