在平面直角坐标系\(xOy\)中,已知椭圆\(C\):\(\dfrac{{{x}^{2}}}{{{a}^{2}}}+\dfrac{{{y}^{2}}}{{{b}^{2}}}=1(a > b > 0)\)的离心率为\(\dfrac{\sqrt{3}}{2}\),左、右焦点分别是\(F_{1}\),\(F_{2}.\)以\(F_{1}\)为圆心、以\(3\)为半径的圆与以\(F_{2}\)为圆心、以\(1\)为半径的圆相交,且交点在椭圆\(C\)上.
\((1)\)求椭圆\(C\)的方程;
\((2)\)设椭圆\(E\):\(\dfrac{{{x}^{2}}}{4{{a}^{2}}}+\dfrac{{{y}^{2}}}{4{{b}^{2}}}=1\),\(P\)为椭圆\(C\)上任意一点,过点\(P\)的直线\(y=kx+m\)交椭圆\(E\)于\(A\),\(B\)两点,射线\(PO\)交椭圆\(E\)于点\(Q\).
\((ⅰ)\)求\(\dfrac{\left| OQ \right|}{\left| OP \right|}\)的值;
\((ⅱ)\)求\(\triangle ABQ\)面积的最大值.