优优班--学霸训练营 > 知识点挑题
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            • 1.
              如图,在\(\triangle ABC\)中,\(∠ACB=90^{\circ}\),\(∠CAB=θ\),\(M\)为\(AB\)的中点\(.\)将\(\triangle ACM\)沿着\(CM\)翻折至\(\triangle A{{"}}CM\),使得\(A{{"}}M⊥MB\),则\(θ\)的取值不可能为\((\)  \()\)
              A.\( \dfrac {π}{9}\)
              B.\( \dfrac {π}{6}\)
              C.\( \dfrac {π}{5}\)
              D.\( \dfrac {π}{3}\)
            • 2.
              如图,\(AB\)是\(⊙O\)的直径,\(AC\)是弦,\(∠BAC\)的平分线\(AD\)交\(⊙O\)于点\(D\),\(DE⊥AC\),交\(AC\)的延长线于点\(E\),\(DF⊥AB\)于点\(F\),且\(AE=8\),\(AB=10\).
              在上述条件下,给出下列四个结论:
              \(①DE=BD\);\(②\triangle BDF\)≌\(\triangle CDE\);\(③CE=2\);\(④DE^{2}=AF⋅BF\),则所有正确结论的序号是\((\)  \()\)
              A.\(①②③\)
              B.\(②③④\)
              C.\(①③④\)
              D.\(①②④\)
            • 3.

              如图,\(PC\)与圆\(O\)相切于点\(C\),直线\(PO\)交圆\(O\)于\(A\),\(B\)两点,弦\(CD\)垂直\(AB\)于\(E.\)则下面结论中正确的有(    )个

              \(①ABEC\)∽\(\triangle DEA②∠ACE=∠ACP\)

              \(③DE^{2}=OE·EP④PC^{2}=PA·AB\)

              A.\(1\)
              B.\(2\)
              C.\(3\)
              D.\(4\)
            • 4.

              如图,\(⊙O\)的半径为\(6\),线段\(AB\)与\(⊙O\)相较于\(C\)、\(D\)两点,\(OB\)与\(⊙O\)相交于点\(E\),\(AC=4\),\(CD=3\),\(∠BOD=∠A\),则\(BE=\)(    )

              A.\(4\)
              B.\(5\)
              C.\(6\)
              D.\(10\)
            • 5.

              直角三角形\(ABC\)中,三内角成等差数列,最短边的长度为\(1{,}P\)为\({\triangle }ABC\)内的一点,且\({∠}APB{=}{∠}APC{=}{∠}CPB{=}120^{{∘}}\),则\(PA+PB+PC=\)

              A.\(\sqrt{11}\)
              B.\(\sqrt{10}\)
              C.\(2\sqrt{2}\)
              D.\(\sqrt{7}\)
            • 6.

              如图,已知\(PA\)和圆\(O\)相切,切点为\(A\),\(PBC\)为割线,\(D\)是圆\(O\)上一点,\(AD\),\(BC\)相交于点\(E.\)若\(F\)为\(CE\)上一点使得\(∠EDF=∠P\),已知\(EF=2\),\(EB=4\),\(PB=8\),则\(PA\)的长为(    )

              A.\(12\)
              B.\(10\)
              C.\(8\)
              D.\(6\)
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