优优班--学霸训练营 > 知识点挑题
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            • 1.

              已知函数\(f(x)=|\lg x|\),\(a > b > 0\),\(f(a)=f(b)\),则\(\dfrac{{a}^{2}+{b}^{2}}{a-b} \)的最小值等于    \((\)    \()\)

              A.\(2\sqrt{2}\)
              B.\(\sqrt{5}\)
              C.\(2+\sqrt{3}\)
              D.\(2\sqrt{3}\)
            • 2. 已知函数\(f(x){=}\begin{cases} {|}\log_{2}x{|}{,}0{ < }x{ < }2 \\ \sin(\dfrac{\pi}{4}x){,}2{\leqslant }x{\leqslant }10 \end{cases}\),若存在实数\(x_{1}{,}x_{2}{,}x_{3}{,}x_{4}\)满足\(f(x_{1}){=}f(x_{2}){=}f(x_{3}){=}f(x_{4})\),且\(x_{1}{ < }x_{2}{ < }x_{3}{ < }x_{4}\),则\(\dfrac{(x_{3}{-}1){⋅}(x_{4}{-}1)}{x_{1}{⋅}x_{2}}\)的取值范围是
              A.\((9{,}21)\)
              B.\((20{,}32)\)
              C.\((8{,}24)\)
              D.\((15{,}25)\)
            • 3.

              已知\(f(x)\)是定义在\(R\)上的周期为\(2\)的函数,当\(x∈(-1,1]\)时,\(f(x)=\begin{cases} -4x^{2}+ \dfrac{9}{8},-1 < x\leqslant 0, \\ \log _{2}x,0 < x\leqslant 1, \end{cases}\),则\(f(f( \dfrac{7}{2}))=\)________.

            • 4.

              计算:\(2^{\log }_{2}{}^{3+\log }{}_{4}{}^{3}=\)_______________.

            • 5.

              已知\(m,n\in R\),集合\(A=\left\{ 2,{{\log }_{7}}m \right\}\),集合\(B=\left\{ m,n \right\}\),若\(A\cap B=\left\{ 0 \right\}\),则\(m+n=\) \((\)  \()\)

              A.\(1\)
              B.\(2\)
              C.\(4\)
              D.\(8\)
            • 6.

              已知定义域为\(R\)的偶函数\(f(x)\)在\([0,+∞)\)上是增函数,若实数\(a\)满足\(f(\log _{2}a)+f(\log _{0.5}a)\leqslant 2f(1)\),则实数\(a\)的最小值是       \((\)  \()\)

              A.\(\dfrac{1}{2}\)
              B.\(1\)
              C.\(\dfrac{3}{2}\)
              D.\(2\)
            • 7.
              化简求值:
              \((1)2 \sqrt {3}× \sqrt[3]{1.5}× \sqrt[6]{12}× \sqrt {(3-π)^{2}}\);
              \((2)\lg 25+ \dfrac {2}{3}\lg 8+\lg 5\cdot \lg 20+(\lg 2)^{2}\).
            • 8.

              如果\(\lg 2=m,\lg 3=n,\)则\(\dfrac{\lg 12}{\lg 15}\)等于                                          \((\)  \()\)

              A.\(\dfrac{2m+n}{1+m+n}\)
              B.\(\dfrac{m+2n}{1+m+n}\)
              C.\(\dfrac{2m+n}{1-m+n}\)
              D.\(\dfrac{m+2n}{1-m+n}\) 
            • 9.

              已知\(x > \)\(1\),则\(\log \)\({\,\!}_{x}\)\(9+\)\({\log }_{27}x \)的最小值是             

            • 10.
              计算:
              \((1)\)计算\(27\;^{ \frac {2}{3}}-2\;^{\log _{2}3}×\log _{2} \dfrac {1}{8}+\log _{2}3×\log _{3}4\);
              \((2)\)已知\(0 < x < 1\),\(x+x^{-1}=3\),求\(x\;^{ \frac {1}{2}}-x\;^{- \frac {1}{2}}\).
            0/40

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