优优班--学霸训练营 > 知识点挑题
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            • 1. 设\(f(x)=\lg (5-x)\).
              \((1)\)若\(10^{f(k)}=10^{f(2)}×10^{f(3)}\),求\(k\)的值;
              \((2)\)若\(f(2m-1) < f(m+1)\),求实数\(m\)的取值范围.
            • 2.

              若实数\(x\),\(y\)满足\(x > y > 0\),且\(\log _{2}x+\log _{2}y=1\),则\(\dfrac{x^{2}{+}y^{2}}{x\mathrm{{-}}y}\)的最小值为____\(.\) 

            • 3.

              已知\(x\),\(y\)是满足\(2x+y=20\)的正数,则\(\lg x+\lg y\)的最大值为________.

            • 4.
              计算题
              \((1)\)求值:\(27^{ \frac {2}{3}}-( \sqrt[3]{-125})^{2}-2^{\log _{2}3}×\log _{2} \dfrac {1}{8}+\log _{2}3×\log _{3}4\)
              \((2)\)求不等式的解集:\(①3^{3-x} < 2\);\(②\log _{5}(x-1) < \dfrac {1}{2}\).
            • 5.

              正项等比数列\(\{ a_{n}\}\)中的\(a_{1}\),\(a_{4033}\)是函数\(f(x)=\dfrac{1}{3}{{x}^{3}}-4{{x}^{2}}+6x-3\)的极值点,则\(\log_{6}a_{2017}{=}(\)  \()\)

              A.\(\dfrac{1}{2}\)
              B.\(1\)
              C.\(2\)
              D.\({-}1\)
            • 6. 化简求值:
              \((1)0.064\;^{- \frac {1}{3}}-(- \dfrac {1}{8})^{0}+16\;^{ \frac {3}{4}}+0.25\;^{ \frac {1}{2}}\)
              \((2) \dfrac {1}{2}\lg 25+\lg 2+( \dfrac {1}{3})\;^{\log _{3}2}-\log _{2}9×\log _{3}2.\)
            • 7.
              计算:\({3}^{lo{g}_{3}4}−{27}^{ \frac{2}{3}}−\lg 0.01+\ln {e}^{3} =\) ______
            • 8.

              已知数列\(\{a_{n}\}\)满足\(\log _{3}a_{n}+1=\log _{3}a_{n+1}(n∈N*)\)且\(a+a_{4}+a_{6}=9\),且\({{\log }_{\frac{1}{3}}}({{a}_{5}}+{{a}_{7}}+{{a}_{9}})\)的值是\((\)   \()\)

              A.\(-5\)
              B.\(-\dfrac{1}{5}\)
              C.\(5\)
              D.\(\dfrac{1}{5}\)
            • 9.

              已知\(a+{{a}^{-1}}=\dfrac{5}{2}(a > 1)\).

              \((1)\)求下列各式的值:\((\)Ⅰ\(){{a}^{-\frac{1}{2}}}+{{a}^{\frac{1}{2}}}\);\((\)Ⅱ\(){{a}^{\frac{3}{2}}}+{{a}^{-\frac{3}{2}}}\);

              \((2)\)已知\(2\lg (x-2y)=\lg x+\lg y\),求\({{\log }_{a}}\dfrac{y}{x}\)的值.

            • 10.
              若\(2^{a}=3^{b}=6\),则\( \dfrac {1}{a}+ \dfrac {1}{b}=(\)  \()\)
              A.\( \dfrac {1}{6}\)
              B.\(6\)
              C.\( \dfrac {5}{6}\)
              D.\(1\)
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