10.
设\(a\),\(b\),\(c\),\(d > 0\),
\((1)\)若\(a+b+c+d=3\),求证:\(\dfrac{{{a}^{3}}}{b+c+d}+\dfrac{{{b}^{3}}}{a+c+d}+\dfrac{{{c}^{3}}}{a+b+d}+\dfrac{{{d}^{3}}}{a+b+c}\geqslant \dfrac{3}{4}\);
\((2)\)求证:\(\dfrac{a}{b+2c+3d}+\dfrac{b}{c+2d+3a}+\dfrac{c}{d+2a+3b}+\dfrac{d}{a+2b+3c}\geqslant \dfrac{2}{3}\).