优优班--学霸训练营 > 知识点挑题
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            • 1.
              若\(x_{1}\),\(x_{2}\),\(x_{3}∈(0,+∞)\),设\(a= \dfrac {x_{1}}{x_{2}},b= \dfrac {x_{2}}{x_{3}},c= \dfrac {x_{3}}{x_{1}}\),则\(a\),\(b\),\(c\)的值\((\)  \()\)
              A.至多有一个不大于\(1\)
              B.至少有一个不小于\(1\)
              C.都大于\(1\)
              D.都小于\(1\)
            • 2.
              已知\(a > 0\),则\( \dfrac {(a-1)(4a-1)}{a}\)的最小值为 ______ .
            • 3.
              设\(x\),\(y\)满足条件\( \begin{cases} x-y+2\geqslant 0 \\ 3x-y-6\leqslant 0 \\ x\geqslant 0,y\geqslant 0\end{cases}\),若目标函数\(z=ax+by(a > 0,b > 0)\)的最大值为\(12\),则\( \dfrac {3}{a}+ \dfrac {2}{b}\)的最小值为\((\)  \()\)
              A.\( \dfrac {25}{6}\)
              B.\( \dfrac {8}{3}\)
              C.\( \dfrac {11}{3}\)
              D.\(4\)
            • 4.
              已知\(a > 0\),则\( \dfrac {(a+1)^{2}}{a}\)的最小值为 ______ .
            • 5.

              当\(x > 1\)时,函数\(y=x+\dfrac{1}{x\mathrm{{-}}1}\)的最小值是____\(.\) 

            • 6.

              已知\(\triangle ABC\)的三个内角\(A\),\(B\),\(C\)对应的边分别为\(a\),\(b\),\(c\),且\(2\cos B(c·\cos A+a·\cos C)=b \).


              \((1)\)证明:\(A\),\(B\),\(C\)成等差数列; 


              \((2)\)若\(\triangle ABC\)的面积为\(\dfrac{3 \sqrt{3}}{2} \),求\(b\)的最小值.

            • 7.

              \(a > 0,b > 0,a+2b=2\),则\(\dfrac{1}{a}+\dfrac{1}{b}\)的最小值为________________ .

            • 8.

              已知\(x{ > }2\),函数\(y{=}\dfrac{4}{x{-}2}{+}x\)的最小值是\((\)  \()\)

              A.\(5\)                                
              B.\(4\)                                
              C.\(6\)                                
              D.\(8\)
            • 9.

              若\(a\),\(b\)都是正数,则\(\left( 1+\dfrac{b}{a} \right)\left( 1+\dfrac{4a}{b} \right)\)的最小值为\((\)    \()\)

              A.\(7\)
              B.\(8\)
              C.\(9\)
              D.\(10\)
            • 10.

              已知函数\(f(x)=|\lg x|\),\(a > b > 0\),\(f(a)=f(b)\),则\(\dfrac{{a}^{2}+{b}^{2}}{a-b} \)的最小值等于    \((\)    \()\)

              A.\(2\sqrt{2}\)
              B.\(\sqrt{5}\)
              C.\(2+\sqrt{3}\)
              D.\(2\sqrt{3}\)
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