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            • 1.

              三棱锥\(A-BCD\)中,\(AB=AC=AD=2\),\(∠BAD=90^{\circ}\),\(∠BAC=60^{\circ}\),则\(\overrightarrow{AB}\)\(·\)\(\overrightarrow{CD}\)等于\((\)  \()\)


              A.\(2\)
              B.\(-2\)
              C.\(-2\sqrt{3}\)
              D.\(2\sqrt{3}\)     
            • 2.

              如图,在三棱柱\(ABC-A_{1}B_{1}C_{1}\)中,\(M\)为\(A_{1}C_{1}\)的中点,若\(\overrightarrow{AB}=\overrightarrow{a}\),\(\overrightarrow{BC}=\overrightarrow{b}\),\(\overset{⇀}{A{A}_{1}}= \overset{⇀}{c} \),则\(\overrightarrow{BM}\)可表示为\((\)    \()\)


              A.\(-\dfrac{1}{2}\overrightarrow{a}+\dfrac{1}{2}\overrightarrow{b}+\overrightarrow{c}\)



              B.\(\dfrac{1}{2}\overrightarrow{a}+\dfrac{1}{2}\overrightarrow{b}+\overrightarrow{c}\)



              C.\(-\dfrac{1}{2}\overrightarrow{a}-\dfrac{1}{2}\overrightarrow{b}+\overrightarrow{c}\)



              D.\(\dfrac{1}{2}\overrightarrow{a}-\dfrac{1}{2}\overrightarrow{b}+\overrightarrow{c}\)


            • 3.

              在平行六面体\(ABCD-A_{1}B_{1}C_{1}D_{1}\) 中,设\( \overrightarrow{A{C}_{1}}=x \overrightarrow{AB}+2y \overrightarrow{BC}+3z \overrightarrow{C{C}_{1}} \),则\(x{+}y{+}z=(\)     \()\)

              A.\( \dfrac{2}{3}\)
              B.\( \dfrac{5}{6}\)              
              C.\( \dfrac{11}{6}\)            
              D.\( \dfrac{7}{6}\)
            • 4.

              如图所示,在平行六面体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,设\( \overrightarrow{A{A}_{1}}= \overrightarrow{a} \),\( \overrightarrow{AB}= \overrightarrow{b} \),\( \overrightarrow{AD}= \overrightarrow{c} \),\(M\),\(N\),\(P\)分别是\(AA_{1}\),\(BC\),\(C_{1}D_{1}\)的中点,则\( \overrightarrow{MP}+ \overrightarrow{N{C}_{1}}= =(\)  \()\)


              A.\( \dfrac{3}{2} \overrightarrow{a}+ \dfrac{1}{2} \overrightarrow{b}+ \dfrac{3}{2} \overrightarrow{c} \) 
              B.\( \overrightarrow{a}+ \dfrac{1}{2} \overrightarrow{c} \)          
              C.\( \dfrac{1}{2} \overrightarrow{a}+ \dfrac{1}{2} \overrightarrow{b}+ \overrightarrow{c} \)
              D.\( \dfrac{3}{2} \overrightarrow{a}+ \dfrac{1}{2} \overrightarrow{b}+ \dfrac{1}{2} \overrightarrow{c} \)
            • 5.
              如图所示,在平行六面体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,设\( \overrightarrow{AA_{1}}= \overrightarrow{a}\),\( \overrightarrow{AB}= \overrightarrow{b}\),\( \overrightarrow{AD}= \overrightarrow{c}\),\(M\),\(N\),\(P\)分别是\(AA_{1}\),\(BC\),\(C_{1}D_{1}\)的中点,则\( \overrightarrow{MP}+ \overrightarrow{NC_{1}}=(\)  \()\)
              A.\( \dfrac {3}{2} \overrightarrow{a}+ \dfrac {1}{2} \overrightarrow{b}+ \dfrac {3}{2} \overrightarrow{c}\)
              B.\( \overrightarrow{a}+ \dfrac {1}{2} \overrightarrow{c}\)
              C.\( \dfrac {1}{2} \overrightarrow{a}+ \dfrac {1}{2} \overrightarrow{b}+ \overrightarrow{c}\)
              D.\( \dfrac {3}{2} \overrightarrow{a}+ \dfrac {1}{2} \overrightarrow{b}+ \dfrac {1}{2} \overrightarrow{c}\)
            • 6.

              如图所示,空间四边形\(OABC\)中,\(\overrightarrow{OA}=a\),\(\overrightarrow{OB}=b\),\(\overrightarrow{OC}=c\),点\(M\)在\(OA\)上,且\(OM=2MA\),点\(N\)为\(BC\)的中点,则\(\overrightarrow{MN}\)等于\((\)    \()\)

              A.\(\dfrac{1}{2}a-\dfrac{2}{3}b+\dfrac{1}{2}c\)
              B.\(-\dfrac{2}{3}a+\dfrac{1}{2}b+\dfrac{1}{2}c\)
              C.\(\dfrac{1}{2}a+\dfrac{1}{2}b-\dfrac{1}{2}c\)
              D.\(-\dfrac{2}{3}a+\dfrac{2}{3}b-\dfrac{1}{2}c\)
            • 7.

              在四面体\(ABCD\)中,\(E\),\(G\)分别是\(CD\),\(BE\)的中点,若空间向量\( \overset{→}{AG}=x \overset{→}{AB}+y \overset{→}{AD}+z \overset{→}{AC} \),则\(x+y+z=\)(    )

              A.\( \dfrac{1}{3} \)
              B.\( \dfrac{1}{2} \)
              C.\(1\)
              D.\(2\)
            • 8. 已知向量 \(a\)\(=(0,2,1)\), \(b\)\(=(-1,1,-2)\),则 \(a\)\(b\)的夹角为\((\)    \()\)
              A.\(0^{\circ}\)
              B.\(45^{\circ}\)
              C.\(90^{\circ}\)
              D.\(180^{\circ}\)
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