优优班--学霸训练营 > 知识点挑题
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            • 1.

              若函数\(f(x)=\dfrac{{{2}^{x}}+1}{{{2}^{x}}-a}(a\in R)\)是奇函数,则使\(f(x) > 4\)成立的\(x\)的取值范围为

              A.\((-∞,{{\log }_{2}}\dfrac{5}{3})\)
              B.\((-{{\log }_{2}}\dfrac{5}{3},0)\)
              C.\((0,{{\log }_{2}}\dfrac{5}{3})\)
              D.\(({{\log }_{2}}\dfrac{5}{3},+∞)\)
            • 2.

              若\({{a}^{10}}=\dfrac{1}{2}\),\({{a}^{m}}=\dfrac{\sqrt{2}}{2}\),则\(m=\)                 

            • 3.

              设等比数列\(\{a_{n}^{{}}\}\)的前\(n\)项和为\(S_{n}^{{}}\),若\(\dfrac{{{S}_{6}}}{{{S}_{3}}}=4,\)则\(\dfrac{{{S}_{9}}}{{{S}_{6}}} =\)(    )

              A.\(3\)
              B.\(\dfrac{13}{4}\)
              C.\(\dfrac{15}{4}\)
              D.\(4\)
            • 4.

              已知函数\(f(x)=\begin{cases}{\log }_{3}x,x > 0 \\ {2}^{x},x\leqslant 0\end{cases} \),则\(f(f( \dfrac{1}{9}))= \)                    

            • 5.

              计算:

              \((1){{\lg }^{2}}5+\lg 2\cdot \lg 5+\lg 2\)       \((2)2\sqrt{3}\times \sqrt[6]{12}\times \sqrt[3]{\dfrac{3}{2}}\)

            • 6.

              若函数\(f(x)\)满足\(f(4)=2\),且对于任意正数\({{x}_{1}},{{x}_{2}}\),都有\(f({{x}_{1}}\cdot {{x}_{2}})=f({{x}_{1}})+f({{x}_{2}})\)成立\(.\)则\(f(x)\)可能为

              A.\(f(x)=\sqrt{x}\)
              B.\(f(x)=\dfrac{x}{2}\)      
              C.\(f(x)={{\log }_{2}}x\)
              D.\(f(x)={{2}^{x}}\)
            • 7.

              函数\(f(x)={{2}^{x}}+3x-7\)的零点所在的区间是(    )

              A.\((-1,0)\)
              B.\((0,1)\)
              C.\((1,2)\)
              D.\((2,3)\)
            • 8.

              已知\(a=2^{1.3}\) , \(b=4^{0.7}\) , \(c=\ln 6\),则\(a\),\(b\),\(c\)的大小关系为\((\)  \()\)       

              A.\(a < b < c\)
              B.\(b < c < a\)
              C.\(c < a < b\)
              D.\(c < b < a\)
            • 9.

              若\(a={{\log }_{4}}3\),则\({{2}^{a}}+{{2}^{-a}}=\)_____.

            • 10.
              计算下列各式.
              \((1) \dfrac {1}{2}\lg 25+\lg 2-\lg \sqrt {0.1}-\log _{2}9×\log _{3}2\);
              \((2)64^{ \frac {1}{3}}-(- \dfrac {2}{3})^{0}+( \dfrac {1}{16})^{- \frac {1}{2}}+\lg 20+\log _{100}25\).
            0/40

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