在数列\(\{a_{n}\}\)与\(\{b_{n}\}\)中,\(a_{1}=1\),\(b_{1}=4\),数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}\)满足\(nS_{n+1}-(n+3)S_{n}=0\),\(2a_{n+1}\)为\(b_{n}\)与\(b_{n+1}\)的等比中项,\(n∈N*\)
\((1)\)求\(a_{2}\),\(b_{2}\)的值;
\((2)\)求数列\(\{a_{n}\}\)与\(\{b_{n}\}\)的通项公式;
\((3)\)设\({{T}_{n}}={{(-1)}^{{{a}_{1}}}}{{b}_{1}}+{{(-1)}^{{{a}_{2}}}}{{b}_{2}}+\cdot \cdot \cdot +{{(-1)}^{{{a}_{n}}}}{{b}_{n}}\),\(n∈N*\),证明\(|T_{n}| < 2n^{2}\),\(n\geqslant 3\).