共50条信息
设\(z\)是虚数,\(ω=z+\dfrac{1}{z}\)是实数,且\(-1 < ω < 2\)
\((1)\)求\(|z|\)的值及\(z\)的实部的取值范围;
\((2)\)设\(u=\dfrac{1-z}{1+z} \),求证:\(u\)为纯虚数;
\((3)\)求\(ω-u^{2}\)的最小值
\((1)\dfrac{{2}+{2i}}{{{({1}-{i})}^{{2}}}}+{{\left( \dfrac{\sqrt{{2}}}{{1}+{i}} \right)}^{{2016}}}\);
\((2)i+i^{2}+…+i^{2017}\).
\((1)\dfrac{{2}+{2i}}{{{({1}-{i})}^{{2}}}}+{{\left( \dfrac{\sqrt{{2}}}{{1}+{i}} \right)}^{{2010}}}\);
\((2)(4-i^{5})(6+2i^{7})+(7+i^{11})(4-3i)\).
计算:\((1)\) \((4-{{i}^{5}})(6+2{{i}^{7}})+(7+{{i}^{11}})(4-3i)\) \((2)\) \(\dfrac{5{{(4+i)}^{2}}}{i(2+i)}\)
计算\((4-{{i}^{5}})(6+2{{i}^{7}})+(7+{{i}^{11}})(4-3i)\)
已知\(1+x+x^{2}=0\),求:
\((1)1+x+x^{2}+…+x^{100}\);
\((2)x^{2001}+x^{2002}+…+x^{2007}\).
计算\((1)\dfrac{2+2i}{1-i}+{{\left( \dfrac{\sqrt{2}}{1+i} \right)}^{2016}}\) \((2)\)计算 \(\int_{-2}^{0}{\sqrt{4-{{x}^{2}}}}dx\)
进入组卷