一只药用昆虫的产卵数\(y\)与一定范围内的温度\(x\)有关, 现收集了该种药用昆虫的\(6\)组观测数据如下表:
温度\(x/^{\circ}C\) | \(21\) | \(23\) | \(24\) | \(27\) | \(29\) | \(32\) |
产卵数\(y/\)个 | \(6\) | \(11\) | \(20\) | \(27\) | \(57\) | \(77\) |
经计算得:\(\bar{x}=\dfrac{1}{6}\sum\limits_{i=1}^{6}{{{x}_{i}}}=26\),\(\bar{y}=\dfrac{1}{6}\sum\limits_{i=1}^{6}{{{y}_{i}}}=33\),\(\sum\limits_{i=1}^{6}{({{x}_{i}}-\bar{x})({{y}_{i}}}-\bar{y})=557\),\(\sum\limits_{i=1}^{6}{{{({{x}_{i}}-\bar{x})}^{2}}}=84\),\(\sum\limits_{i=1}^{6}{({{y}_{i}}}-\bar{y}{{)}^{2}}=3930\),线性回归模型的残差平方和\(\sum\limits_{i=1}^{6}{({{y}_{i}}}-{{\hat{y}}_{i}}{{)}^{2}}=236.64\),\(e^{8.0605}≈3167\),其中\(x_{i}\), \(y_{i}\)分别为观测数据中的温度和产卵数,\(i=1\), \(2\), \(3\), \(4\), \(5\), \(6\).
\((\)Ⅰ\()\)若用线性回归模型,求\(y\)关于\(x\)的回归方程\(\hat{y}=\hat{b}x+\hat{a}(\)精确到\(0.1)\);
\((\)Ⅱ\()\)若用非线性回归模型求得\(y\)关于\(x\)的回归方程为\(\hat{y}=0.06e^{0.2303x}\),且相关指数\(R^{2}=0.95\).
\(( i )\)试与\((\)Ⅰ\()\)中的回归模型相比,用\(R^{2}\)说明哪种模型的拟合效果更好.
\((ii)\)用拟合效果好的模型预测温度为\(35^{\circ}C\)时该种药用昆虫的产卵数\((\)结果取整数\()\).
附:一组数据\((x_{1},y_{1})\), \((x_{2},y_{2})\), \(...\),\((x_{n},y_{n})\), 其回归直线\(\hat{y}=\hat{b}x+\hat{a}\)的斜率和截距的最小二乘估计为
\(\hat{b}=\dfrac{\sum\limits_{i=1}^{n}{({{x}_{i}}-\bar{x})({{y}_{i}}}-\bar{y})}{\sum\limits_{i=1}^{n}{{{({{x}_{i}}-\bar{x})}^{2}}}},\hat{a}=\bar{y}−\hat{b}\bar{x}\);相关指数\(R^{2}=1-\dfrac{\sum\limits_{i=1}^{n}{({{y}_{i}}}-{{{\hat{y}}}_{i}}{{)}^{2}}}{\sum\limits_{i=1}^{n}{({{y}_{i}}}-\bar{y}{{)}^{2}}}\).