优优班--学霸训练营 > 知识点挑题
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            • 1.
              函数\(f(x)=\sin ^{2}(x+ \dfrac {π}{4})+\cos ^{2}(x- \dfrac {π}{4})-1\)是\((\)  \()\)
              A.周期为\(π\)的奇函数
              B.周期为\(π\)的偶函数
              C.周期为\(2π\)的奇函数
              D.周期为\(2π\)的偶函数
            • 2.
              若复数\(z=(\cos θ- \dfrac {4}{5})+(\sin θ- \dfrac {3}{5})i\)是纯虚数\((i\)为虚数单位\()\),则\(\tan (θ- \dfrac {π}{4})\)的值为\((\)  \()\)
              A.\(7\)
              B.\(- \dfrac {1}{7}\)
              C.\(-7\)
              D.\(-7\)或\(- \dfrac {1}{7}\)
            • 3.
              设\(a=\sin 17^{\circ}\cos 45^{\circ}+\cos 17^{\circ}\sin 45^{\circ}\),\(b=2\cos ^{2}13^{\circ}-1\),\(c= \dfrac { \sqrt {3}}{2}\),则有\((\)  \()\)
              A.\(a < b < c\)
              B.\(b < c < a\)
              C.\(c < a < b\)
              D.\(b < a < c\)
            • 4.
              已知\(\tan ( \dfrac {π}{4}+θ)=3,{求}\sin 2θ-2\cos ^{2}θ\)的值.
            • 5.
              已知\(α∈(0,π)\),若\(\tan ( \dfrac {π}{4}-α)= \dfrac {1}{3}\),则\(\sin 2α=(\)  \()\)
              A.\(- \dfrac {4}{5}\)
              B.\( \dfrac {4}{5}\)
              C.\(- \dfrac {5}{4}\)
              D.\( \dfrac {5}{4}\)
            • 6.
              若\(\sin α= \dfrac {1}{5}\),则\(\cos 2α=(\)  \()\)
              A.\( \dfrac {23}{25}\)
              B.\(- \dfrac {2}{25}\)
              C.\(- \dfrac {23}{25}\)
              D.\( \dfrac {2}{25}\)
            • 7.
              已知\(a=\cos ^{2} \dfrac {π}{6}-\sin ^{2} \dfrac {π}{6}\),\(b=\sin 1\),\(c= \dfrac {\tan 30 ^{\circ} }{1-\tan ^{2}30 ^\circ }\),则\(a\),\(b\),\(c\)的大小关系是\((\)  \()\)
              A.\(a < b < c\)
              B.\(a > b > c\)
              C.\(c > a > b\)
              D.\(a < c < b\)
            • 8.
              在\(\triangle ABC\)中,\(a=4\),\(b=5\),\(c=6\),则\( \dfrac {\sin 2A}{\sin C}=\) ______ .
            • 9.
              已知\(\sin \dfrac {θ}{2}+\cos \dfrac {θ}{2}= \dfrac {2 \sqrt {3}}{3}\),那么\(\sin θ\)的值为 ______ ,\(\cos 2θ\)的值为 ______ .
            • 10.
              若角\(α\)的终边经过点\(P(1,-2)\),则\(\tan 2α\)的值为 ______ .
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