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            • 1. 已知数列\(\{{{a}_{n}}\}\)满足\({{a}_{1}}=\sqrt{2}\)\(a_{n}^{2}-a_{n-1}^{2}=2n\left(n\geqslant 2\right) \),且\({{a}_{n}} > 0\)

              \((1)\)求\(\{{{a}_{n}}\}\)的通项;

              \((2)\)设\(\{{{a}_{n}}\}\)的前\(n\)项和为\({{S}_{n}}\),用数学归纳法证明:\({{S}_{n}} < \dfrac{1}{2}{{(n+1)}^{2}}\)

            • 2.

              已知函数\(f(x)=ax- \dfrac{b}{x}-2\ln x\),\(f(1)=0\).

              \((1)\)若函数\(f(x)\)在其定义域内为单调函数,求实数\(a\)的取值范围?

              \((2)\)若函数\(f(x)\)的图像在\(x=1\)处的切线的斜率为\(0\),且\(a_{n+1}=f′\left( \left. \dfrac{1}{a_{n}+1} \right. \right)-na_{n}+1\),若\(a_{1}\geqslant 3\),求证:\(a_{n}\geqslant n+2\).

            • 3.

              观察下列等式

              \(1 > \dfrac{1}{2} \)

              \(1+ \dfrac{1}{2}+ \dfrac{1}{3} > 1 \)
              \(1+ \dfrac{1}{2}+ \dfrac{1}{3}+ \dfrac{1}{4}+ \dfrac{1}{5}+ \dfrac{1}{6}+ \dfrac{1}{7} > \dfrac{3}{2} \)
              \(1+ \dfrac{1}{2}+ \dfrac{1}{3}+...+ \dfrac{1}{15} > 2 \)
              \(1+ \dfrac{1}{2}+ \dfrac{1}{3}+...+ \dfrac{1}{31} > \dfrac{5}{2} \)

              \((1)\)从上述不等式归纳出一个与正整数\(n\)有关的一般不等式;

              \((2)\)证明你归纳得到的不等式.

            • 4. 若\(f(n)=1+ \dfrac {1}{ \sqrt {2}}+ \dfrac {1}{ \sqrt {3}}+…+ \dfrac {1}{ \sqrt {n}}\),\(n∈N\),当\(n\geqslant 3\)时,证明:\(f(n) > \sqrt {n+1}\).
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