优优班--学霸训练营 > 知识点挑题
全部资源
          排序:
          最新 浏览

          50条信息

            • 1. 已知两圆\({{x}^{2}}+{{y}^{2}}=1\)与\({{(x-a)}^{2}}+{{(y-a)}^{2}}=1(a\ne 0)\)有公共点,则两圆的相交弦长不小于\(\sqrt{2}\)的概率是

              A.\(\dfrac{\sqrt{2}}{4}\)
              B.\(\dfrac{1}{2}\)
              C.\(\dfrac{\sqrt{2}}{2}\)
              D.\(\dfrac{1}{4}\)
            • 2.

              已知圆\({{x}^{2}}+{{y}^{2}}-2x-5=0\)和圆\({{x}^{2}}+{{y}^{2}}+2x-4y-4=0\)的交点为\(A,B\),则线段\(AB\)的垂直平分线方程为\((\)   \()\)

              A.\(x-y+1=0\)
              B.\(x-2y+1=0\)
              C.\(x+y-1=0\)
              D.\(2x-y+1=0\)
            • 3. 已知圆\(C_{1}:x^{2}+y^{2}+2x+8y-8=0\)与圆\(C_{2}:x^{2}+y^{2}-4x-4y-2=0\)相交,则圆\(C_{1}\)与圆\(C_{2}\)的公共弦所在的直线的方程为\((\)  \()\)
              A.\(x+2y+1=0\)
              B.\(x+2y-1=0\)
              C.\(x-2y+1=0\)
              D.\(x-2y-1=0\)
            • 4.

              以圆\(C_{1}\):\({{x}^{2}}+{{y}^{2}}+4x+1=0\)与圆\(C_{2}\):\({{x}^{2}}+{{y}^{2}}+2x+2y{+}1=0\)的公共弦为直径的圆的方程为(    )

              A.\({{\left( x-1 \right)}^{2}}+{{\left( y-1 \right)}^{2}}=1\)
              B.\({{\left( x-\dfrac{3}{5} \right)}^{2}}+{{\left( y-\dfrac{3}{5} \right)}^{2}}=2\)
              C.\({{\left( x{+}1 \right)}^{2}}+{{\left( y{+}1 \right)}^{2}}=1\)
              D.\({{\left( x{+}\dfrac{3}{5} \right)}^{2}}+{{\left( y{+}\dfrac{3}{5} \right)}^{2}}=2\)
            0/40

            进入组卷