优优班--学霸训练营 > 知识点挑题
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            • 1.
              已知函数\(f(x)=1-2\sin ^{2}x\)
              \((1)f( \dfrac {π}{6})=\) ______ ;
              \((2)\)求函数\(f(x)\)在区间\([- \dfrac {π}{4}, \dfrac {π}{6}]\)上的最大值和最小值.
            • 2.
              已知锐角\(α\)满足\(\cos (α- \dfrac {π}{4})=\cos 2α\),则\(\sin α\cos α\)等于\((\)  \()\)
              A.\( \dfrac {1}{4}\)
              B.\(- \dfrac {1}{4}\)
              C.\( \dfrac { \sqrt {2}}{4}\)
              D.\(- \dfrac { \sqrt {2}}{4}\)
            • 3.
              已知函数\(f(x)=\cos x(\sin x+ \sqrt {3}\cos x)- \dfrac { \sqrt {3}}{2}\),\(x∈R\),设\(a > 0\),若函数\(g(x)=f(x+α)\)为奇函数,则\(α\)的值为 ______ .
            • 4.
              已知点\(P_{1}\),\(P_{2}\)为曲线\(y= \sqrt {2}\sin ωx-\cos ωx(x∈R)(\)常数\(ω > 0)\)的两个相邻的对称中心,若该曲线在点\(P_{1}\),\(P_{2}\)处的切线互相垂直,则\(ω\)的值为\((\)  \()\)
              A.\( \dfrac { \sqrt {3}}{3}\)
              B.\( \dfrac { \sqrt {2}}{2}\)
              C.\( \sqrt {2}\)
              D.\( \sqrt {3}\)
            • 5.
              已知\(\sin (x- \dfrac {π}{4})= \dfrac {3}{5}\),则\(\cos (x+ \dfrac {π}{4})=(\)  \()\)
              A.\( \dfrac {4}{5}\)
              B.\( \dfrac {3}{5}\)
              C.\(- \dfrac {4}{5}\)
              D.\(- \dfrac {3}{5}\)
            • 6.
              若\(\tan (α+ \dfrac {π}{4})=-3\),则\(\cos 2α+2\sin 2α=(\)  \()\)
              A.\( \dfrac {9}{5}\)
              B.\(1\)
              C.\(- \dfrac {3}{5}\)
              D.\(- \dfrac {7}{5}\)
            • 7.
              已知函数\(f(x)= \dfrac {\cos 2x}{\sin x+\cos x}\).
              \((\)Ⅰ\()\)求\(f(x)\)的定义域;
              \((\)Ⅱ\()\)求\(f(x)\)的取值范围.
            • 8.
              已知\(\tan (x+ \dfrac {π}{4})=-2\),则\(\sin 2x+2\cos ^{2}x=\) ______
            • 9.
              若\(2\cos ^{2}( \dfrac {π}{4}- \dfrac {α}{2}- \dfrac {β}{2})=1+3\sin (α-β)\),\(α,β∈(0, \dfrac {π}{2})\),则\( \dfrac {\tan α}{\tan \beta }=\) ______ .
            • 10.
              \(\log _{2}(\cos \dfrac {7π}{4})\)的值为\((\)  \()\)
              A.\(-1\)
              B.\(- \dfrac {1}{2}\)
              C.\( \dfrac {1}{2}\)
              D.\( \dfrac { \sqrt {2}}{2}\)
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