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            • 1. (请用空间向量求解)
              已知正四棱柱ABCD-A1B1C1D1中,AB=1,AA1=3,E,F分别是棱AA1,CC1上的点,且满足AE=2EA1,CF=2FC1
              (1)求异面直线EC1,DB1所成角的余弦值;
              (2)求面EB1C1与面FAD所成的锐二面角的余弦值.
            • 2.
              如图,在三棱柱\(ABC-A_{1}B_{1}C_{1}\)中,\(A_{1}B⊥\)平面\(ABC\),\(AB⊥AC\).

              \((1)\)求证:\(AC⊥BB_{1}\);

              \((2)\)若\(AB=AC=A_{1}B=2\),在棱\(B_{1}C_{1}\)上确定一点\(P\),  使二面角\(P-AB-A_{1}\)的平面角的余弦值为

            • 3.
              如图,在矩形\(ABCD\)中,点\(E\)为边\(AD\)上的点,点\(F\)为边\(CD\)的中点,\(AB=AE= \dfrac {2}{3}AD\),现将\(\triangle ABE\)沿\(BE\)边折至\(\triangle PBE\)位置,且平面\(PBE⊥\)平面\(BCDE\).
              \((\)Ⅰ\()\)求证:平面\(PBE⊥\)平面\(PEF\);
              \((\)Ⅱ\()\) 求二面角\(E-PF-C\)的大小.
            • 4.
              如图,在四棱柱\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,侧面\(ADD_{1}A_{1}⊥\)底面\(ABCD\),\(D_{1}A=D_{1}D= \sqrt {2}\),底面\(ABCD\)为直角梯形,其中\(BC/\!/AD\),\(AB⊥AD\),\(AD=2AB=2BC=2\),\(O\)为\(AD\)中点.
              \((\)Ⅰ\()\)求证:\(A_{1}O/\!/\)平面\(AB_{1}C\);
              \((\)Ⅱ\()\)求锐二面角\(A-C_{1}D_{1}-C\)的余弦值.
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