优优班--学霸训练营 > 知识点挑题
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            • 1.
              如图\(1\),在高为\(2\)的梯形\(ABCD\)中,\(AB/\!/CD\),\(AB=2\),\(CD=5\),过\(A\)、\(B\)分别作\(AE⊥CD\),\(BF⊥CD\),垂足分别为\(E\)、\(F.\)已知\(DE=1\),将梯形\(ABCD\)沿\(AE\)、\(BF\)同侧折起,得空间几何体\(ADE-BCF\),如图\(2\).

              \((\)Ⅰ\()\)若\(AF⊥BD\),证明:\(DE⊥BE\);
              \((\)Ⅱ\()\)若\(DE/\!/CF\),\(CD= \sqrt {3}\),在线段\(AB\)上是否存在点\(P\)使得\(CP\)与平面\(ACD\)所成角的正弦值为\( \dfrac { \sqrt {35}}{35}\)?并说明理由.
            • 2.
              在正方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(E\)是\(C_{1}C\)的中点,则直线\(BE\)与平面\(B_{1}BD\)所成的角的正弦值为\((\)  \()\)
              A.\(- \dfrac { \sqrt {10}}{5}\)
              B.\( \dfrac { \sqrt {10}}{5}\)
              C.\(- \dfrac { \sqrt {15}}{5}\)
              D.\( \dfrac { \sqrt {15}}{5}\)
            • 3.
              如图,在四棱锥\(P-ABCD\)中,\(PA⊥\)底面\(ABCD\),\(AD⊥AB\),\(AB/\!/DC\),\(AD=DC=AP=2\),\(AB=1\),点\(E\)为棱\(PC\)的中点.
              \((\)Ⅰ\()\)证明:\(BE⊥DC\);
              \((\)Ⅱ\()\)求直线\(BE\)与平面\(PBD\)所成角的正弦值;
              \((\)Ⅲ\()\)若\(F\)为棱\(PC\)上一点,满足\(BF⊥AC\),求二面角\(F-AB-P\)的余弦值.
            • 4.
              如图,四棱柱\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(A_{1}D⊥\)平面\(ABCD\),底面\(ABCD\)是边长为\(1\)的正方形,侧棱\(AA_{1}=2\).
              \((\)Ⅰ\()\)求证:\(C_{1}D/\!/\)平面\(ABB_{1}A_{1}\);
              \((\)Ⅱ\()\)求直线\(BD_{1}\)与平面\(A_{1}C_{1}D\)所成角的正弦值;
              \((\)Ⅲ\()\)求二面角\(D-A_{1}C_{1}-A\)的余弦值.
            • 5.
              如图,在四棱锥\(S-ABCD\)中,\(SD⊥\)底面\(ABCD\),底面\(ABCD\)是正方形,且\(SD=AD\),\(E\)是\(SA\)的中点.
              \((1)\)求证:直线\(BA⊥\)平面\(SAD\);
              \((2)\)求直线\(SA\)与平面\(BED\)的夹角的正弦值.
            • 6.
              如图,在三棱锥\(P-ABC\)中,\(AB=BC=2 \sqrt {2}\),\(PA=PB=PC=AC=4\),\(O\)为\(AC\)的中点.
              \((1)\)证明:\(PO⊥\)平面\(ABC\);
              \((2)\)若点\(M\)在棱\(BC\)上,且二面角\(M-PA-C\)为\(30^{\circ}\),求\(PC\)与平面\(PAM\)所成角的正弦值.
            • 7.
              在长方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(AB=BC=2\),\(AC_{1}\)与平面\(BB_{1}C_{1}C\)所成的角为\(30^{\circ}\),则该长方体的体积为\((\)  \()\)
              A.\(8\)
              B.\(6 \sqrt {2}\)
              C.\(8 \sqrt {2}\)
              D.\(8 \sqrt {3}\)
            • 8.
              已知正四棱柱\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(AB=2\),\(CC_{1}=2 \sqrt {2}\),\(E\)为\(CC_{1}\)的中点,则直线\(AC_{1}\)与平面\(BED\)的距离为\((\)  \()\)
              A.\(2\)
              B.\( \sqrt {3}\)
              C.\( \sqrt {2}\)
              D.\(1\)
            • 9.
              已知三棱锥\(S-ABC\)中,底面\(ABC\)为边长等于\(2\)的等边三角形,\(SA\)垂直于底面\(ABC\),\(SA=3\),
              \((1)\)如图建立空间直角坐标系,写出\( \overrightarrow{SB}\)、\( \overrightarrow{SC}\)的坐标;
              \((2)\)求直线\(AB\)与平面\(SBC\)所成角的正弦值.
            • 10.
              如图,已知三棱锥\(O-ABC\)的侧棱\(OA\),\(OB\),\(OC\)两两垂直,且\(OA=1\),\(OB=OC=2\),\(E\)是\(OC\)的中点.
              \((1)\)求异面直线\(BE\)与\(AC\)所成角的余弦值;
              \((2)\)求直线\(BE\)和平面\(ABC\)的所成角的正弦值.
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