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            • 1.
              如图,四棱柱\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(A_{1}D⊥\)平面\(ABCD\),底面\(ABCD\)是边长为\(1\)的正方形,侧棱\(AA_{1}=2\).
              \((\)Ⅰ\()\)求证:\(C_{1}D/\!/\)平面\(ABB_{1}A_{1}\);
              \((\)Ⅱ\()\)求直线\(BD_{1}\)与平面\(A_{1}C_{1}D\)所成角的正弦值;
              \((\)Ⅲ\()\)求二面角\(D-A_{1}C_{1}-A\)的余弦值.
            • 2.

              如图,在一个\({{60}^{o}}\)的二面角的棱上有两点\(A,B\),线段\(AC,BD\)分别在这两个面内,且都垂直于棱\(AB\),\(AB=AC=a\),\(BD=2a\),则\(CD\)的长为\((\)    \()\)  

              A.\(2a\)
              B.\(\sqrt{5}a\)
              C.\(a\)
              D.\(\sqrt{3}a\)
            • 3. 如图,四棱锥\(P-ABCD\)中,\(PD⊥\)平面\(ABCD\),底面\(ABCD\)是正方形,\(PD=AB=2\),\(E\)为\(PC\)中点.
              \((1)\)求证:\(DE⊥\)平面\(PCB\);
              \((2)\)求点\(C\)到平面\(DEB\)的距离;
              \((3)\)求二面角\(E-BD-P\)的余弦值.
            • 4.
              如图,在梯形\(ABCD\)中,\(AB/\!/CD\),\(AD=DC=CB=1\),\(∠ABC=60^{\circ}\),四边形\(ACFE\)为矩形,平面\(ACFE⊥\)平面\(ABCD\),\(CF=1\).
              \((\)Ⅰ\()\)求证:\(BC⊥\)平面\(ACFE\);
              \((\)Ⅱ\()\)点\(M\)在线段\(EF\)上运动,设平面\(MAB\)与平面\(FCB\)所成二面角的平面角为\(θ(θ\leqslant 90^{\circ})\),试求\(\cos θ\)的取值范围.
            • 5.
              如图甲,直角梯形\(ABCD\)中,\(AB/\!/CD\),\(∠DAB= \dfrac {π}{2}\),点\(M\)、\(N\)分别在\(AB\),\(CD\)上,且\(MN⊥AB\),\(MC⊥CB\),\(BC=2\),\(MB=4\),现将梯形\(ABCD\)沿\(MN\)折起,使平面\(AMND\)与平面\(MNCB\)垂直\((\)如图乙\()\).
              \((1)\)求证:\(AB/\!/\)平面\(DNC\);
              \((2)\)当\(DN\)的长为何值时,二面角\(D-BC-N\)的大小为\(30^{\circ}\)?
            • 6.
              等腰直角三角形\(ABC\)中,\(AB=BC=1\),\(M\)为\(AC\)中点,沿\(BM\)把它折成二面角,折后\(A\)与\(C\)的距离为\(1\),则二面角\(C-BM-A\)的大小为\((\)  \()\)
              A.\(30^{\circ}\)
              B.\(60^{\circ}\)
              C.\(90^{\circ}\)
              D.\(120^{\circ}\)
            • 7.
              如图,已知矩形\(ABCD\)中,\(AB=2\),\(AD=1\),\(M\)为\(DC\)的中点\(.\)将\(\triangle ADM\)沿\(AM\)折起,使得平面\(ADM⊥\)平面\(ABCM\).
              \((1)\)求证:\(AD⊥BM\);
              \((2)\)求\(DC\)与平面\(ADM\)所成的角的正弦值;
              \((3)\)若点\(E\)是线段\(DB\)上的一动点,问点\(E\)在何位置时,二面角\(E-AM-D\)的余弦值为\( \dfrac { \sqrt {5}}{5}\).
            • 8.
              如图,四棱锥\(P-ABCD\)中,底面\(ABCD\)为平行四边形,\(AB=2AD=4\),\(BD=2 \sqrt {3}\),\(PD⊥\)底面\(ABCD\).
              \((\)Ⅰ\()\)证明:平面\(PBC⊥\)平面\(PBD\);
              \((\)Ⅱ\()\)若二面角\(P-BC-D\)大小为\( \dfrac {π}{4}\),求\(AP\)与平面\(PBC\)所成角的正弦值.
            • 9.

              二面角\(α-\) \(l\)\(-β\)等于\(120^{\circ}\),\(A\)、\(B\)是棱 \(l\)上两点,\(AC\)、\(BD\)分别在半平面\(α\)、\(β\)内,\(AC⊥\) \(l\),\(BD⊥\) \(l\),且\(AB=AC=BD=1\),则\(CD\)的长等于(    )

              A.\( \sqrt{2} \)    
              B.\( \sqrt{3} \)      
              C.\(2\)      
              D.\( \sqrt{5} \)
            • 10.

              如图,菱形\(ABCD\)的对角线\(AC\)\(BD\)交于点\(O\)\(AB\)\(=5\),\(AC\)\(=6\),点\(E\)\(F\)分别在\(AD\)\(CD\)上,\(AE\)\(=\)\(CF\)\(=\dfrac{5}{4}\),\(EF\)\(BD\)于点\(H\)\(.\)将\(\triangle \)\(DEF\)沿\(EF\)折到\(\triangle {D}{{'}}EF\)的位置,\(O{D}{{'}}=\sqrt{10}\) .


              \((\)Ⅰ\()\)证明:\({D}{{'}}H\bot \)平面\(ABCD\)

              \((\)Ⅱ\()\)求二面角\(B-{D}{{'}}A-C\)的正弦值\(.\)  

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