4.
已知点\(P\)为双曲线\( \dfrac {x^{2}}{a^{2}}- \dfrac {y^{2}}{b^{2}}=1(a > 0,b > 0)\)的右支上一点,\(F_{1}\)、\(F_{2}\)为双曲线的左、右焦点,使 \(( \overrightarrow{OP}+ \overrightarrow{OF_{2}})\cdot \overrightarrow{F_{2}P}=0(O\)为坐标原点\()\),且\(| \overrightarrow{PF_{1}}|= \sqrt {3}| \overrightarrow{PF_{2}}|\),则双曲线离心率为\((\) \()\)