优优班--学霸训练营 > 知识点挑题
全部资源
          排序:
          最新 浏览

          50条信息

            • 1.
              公比为\(3\)的等比数列\(\{a_{n}\}\)的各项都是正数,且\(a_{1}a_{5}=9\),则\(\log _{3}a_{6}=(\)  \()\)
              A.\(7\)
              B.\(6\)
              C.\(5\)
              D.\(4\)
            • 2.
              正项等比数列\(\{a_{n}\}\)中,存在两项\(a_{m}\)、\(a_{n}\)使得\( \sqrt {a_{m}\cdot a_{n}}=2a_{1}\),且\(a_{6}=a_{5}+2a_{4}\),则\( \dfrac {1}{m}+ \dfrac {4}{n}\)的最小值是\((\)  \()\)
              A.\( \dfrac {3}{2}\)
              B.\(2\)
              C.\( \dfrac {7}{3}\)
              D.\( \dfrac {9}{4}\)
            • 3.
              已知\(S_{n}\)为等比数列\(\{a_{n}\}\)的前\(n\)项和\(⋅\)且\(S_{4}=S_{3}+3a_{3}\),\(a_{2}=9\).
              \((1)\)求数列\(\{a_{n}\}\)的通项公式
              \((2)\)设\(b_{n}=(2n-1)a_{n}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(T_{n}\).
            • 4.
              在等比数列\(\{a_{n}\}\)中,\(a_{2}=3\),\(a_{5}=81\).
              \((\)Ⅰ\()\)求\(a_{n}\);
              \((\)Ⅱ\()\)设\(b_{n}=\log _{3}a_{n}\),求数列\(\{b_{n}\}\)的前\(n\)项和\(S_{n}\).
            • 5.
              已知数列\(\{a_{n}\}\)是等比数列,\(S_{n}\)是它的前\(n\)项和,若\(a_{2}⋅a_{3}=2a_{1}\),且\(a_{4}\)与\(2a_{7}\)的等差中项为\( \dfrac {5}{4}\),求\(S_{5}\).
            • 6.
              已知\(\{a_{n}\}\)是等比数列,\(a_{n} > 0\),\(a_{3}=12\),且\(a_{2}\),\(a_{4}\),\(a_{2}+36\)成等差数列.
              \((1)\)求数列\(\{a_{n}\}\)的通项公式;
              \((2)\)设\(\{b_{n}\}\)是等差数列,且\(b_{3}=a_{3}\),\(b_{9}=a_{5}\),求\(b_{3}+b_{5}+b_{7}+…+b_{2n+1}\).
            • 7.
              等比数列\(\{a_{n}\}\)中,\(a_{4}=2\),\(a_{5}=5\),则数列\(\{\lg a_{n}\}\)的前\(8\)项和等于 ______ .
            • 8.
              在递增的等比数列\(\{a_{n}\}\)中,已知\(a_{1}+a_{n}=34\),\(a_{3}⋅a_{n-2}=64\),且前\(n\)项和为\(S_{n}=42\),则\(n=(\)  \()\)
              A.\(3\)
              B.\(4\)
              C.\(5\)
              D.\(6\)
            • 9.
              等比数列\(\{a_{n}\}\)满足\(a_{n} > 0\),且\(a_{2}a_{8}=4\),则\(\log _{2}a_{1}+\log _{2}a_{2}+\log _{2}a_{3}+…+\log _{2}a_{9}=\) ______ .
            • 10.
              等比数列\(\{a_{n}\}\)的各项均为正数,\(2a_{5}\),\(a_{4}\),\(4a_{6}\)成等差数列,且满足\(a_{4}=4a_{3}^{2}\),数列\(\{b_{n}\}\)的前\(n\)项和\(S_{n}= \dfrac {(n+1)b_{n}}{2}\),\(n∈N*\),且\(b_{1}=1\).
              \((\)Ⅰ\()\)求数列\(\{a_{n}\}\)和\(\{b_{n}\}\)的通项公式;
              \((\)Ⅱ\()\)设\(c_{n}= \dfrac {b_{2n+5}}{b_{2n+1}b_{2n+3}}a_{n}\),\(n∈N*\),求证:\( \sum\limits_{k=1}^{n}c_{k} < \dfrac {1}{3}\).
            0/40

            进入组卷