在四边形\(ABCD\)中,对角线\(AC\),\(BD\)垂直相交于点\(O\),且\(OA=OB=OD=4\),\(OC=3\).
将\(\triangle BCD\)沿\(BD\)折到\(\triangle BED\)的位置,使得二面角\(E-BD-A\)的大小为\(90^{\circ}(\)如图\().\)已知\(Q\)为\(EO\)的中点,点\(P\)在线段\(AB\)上,且\(AP= \sqrt {2}\).
\((\)Ⅰ\()\)证明:直线\(PQ/\!/\)平面\(ADE\);
\((\)Ⅱ\()\)求直线\(BD\)与平面\(ADE\)所成角\(θ\)的正弦值.