共50条信息
在正方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,有下面结论:
\(①AC/\!/\)平面\(CB_{1}D_{1}\);\(②AC_{1}⊥\)平面\(CB_{1}D_{1}\);\(③AC_{1}\)与底面\(ABCD\)所成角的正切值为\(\dfrac{\sqrt{{2}}}{{2}}\);\(④AD_{1}\)与\(BD\)为异面直线.
其中正确结论的序号是________.
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