设椭圆\(C: \dfrac{{x}^{2}}{{a}^{2}}+ \dfrac{{y}^{2}}{{b}^{2}}=1\left(a > b > 0\right) \)过点\(M\left( \sqrt{2},1\right) \),且焦点为\({F}_{1}\left(- \sqrt{2},0\right) \)
\((\)Ⅰ\()\)求椭圆 \(C\) 的方程;
\((\)Ⅱ\()\)当过点\(P\left(4,1\right) \)的动直线 \(l\) 与椭圆 \(C\) 相交与两不同点 \(A\),\(B\) 时,在线段 \(AB\) 上取点 \(Q\) ,满足\(\left| \overrightarrow{AP}\right|·\left| \overrightarrow{QB}\right|=\left| \overrightarrow{AQ}\right|·\left| \overrightarrow{PB}\right| \),证明:点 \(Q\) 总在某定直线上