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            • 1.

              \(\vartriangle ABC\) 中,若 \({a}^{2}=b\left(b+c\right) \)

              \((1)\)求证:\(A=2B.\)          

              \((2)\)若\(a= \sqrt{3}b \) ,判断 \(\vartriangle ABC\) 的形状

            • 2.

              在\(\triangle ABC\)中,已知内角\(A\),\(B\),\(C\)对边分别是\(a\),\(b\),\(c\),且\(2c\cos B=2a+b\).

              \((1)\)求\(\angle {C}\);
              \((2)\)若\(a+b=6\),\(\triangle ABC\)的面积为\(2\sqrt{3}\),求\(c\).
            • 3.

              在\(∆ABC \)中,内角\(A \),\(B \),\(C \)的对边分别为\(a \),\(b \),\(c \),且\(c\cos B+b\cos C=2a\cos A \).

              \((1)\)求\(A \);

              \((2)\)若\(a=2 \),且\(∆ABC \)的面积为\(\sqrt{3} \),求\(∆ABC \)的周长.

            • 4.

              求值:

              \((1)\sin 50{}^\circ (1+\sqrt{3}\sin 10{}^\circ )\)

              \((2)\dfrac{2{{\cos }^{2}}42{}^\circ +\sin 75{}^\circ \cos 81{}^\circ -1}{\cos 6{}^\circ -\cos 75{}^\circ \cos 81{}^\circ }\)

            • 5. 已知\(\triangle ABC\)的三个内角\(A\),\(B\),\(C\)满足:\(A+C=2B, \dfrac {1}{\cos A}+ \dfrac {1}{\cos C}=- \dfrac { \sqrt {2}}{\cos B}\),求\(\cos \dfrac {A-C}{2}\)的值.
            • 6.
              已知函数\(f(x)= \sqrt {2}\sin (2x- \dfrac {π}{4})+4\cos ^{2}x\).
              \((\)Ⅰ\()\)求函数\(f(x)\)的最小正周期及最小值;
              \((\)Ⅱ\()\)若\(α∈[0, \dfrac {π}{2}]\),且\(f(α)=3\),求\(α\)的值.
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