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            • 1.

              已知\(f(x)= \sqrt{1+x^{2}}\),\(a\neq b\),求证:\(|f(a)-f(b)| < |a-b|\).

            • 2.

              数列\(\{a_{n}\}\)中,\(a_{1}=2\),\(a_{n+1}= \dfrac{n+1}{2n}a_{n}(n∈N^{*}).\)

              \((1)\)证明:数列\(\left\{ \left. \dfrac{a_{n}}{n} \right. \right\}\)是等比数列,并求数列\(\{a_{n}\}\)的通项公式;

              \((2)\)设\(b_{n}= \dfrac{a_{n}}{4n-a_{n}}\),若数列\(\{b_{n}\}\)的前\(n\)项和是\(T_{n}\),求证:\(T_{n} < 2\).

            • 3.

              已知\({{a}_{n}}=\sqrt{1\times 2}+\sqrt{2\times 3}+\sqrt{3\times 4}+\ldots +\sqrt{n(n+1)}\),\(n∈N^{*}\),求证:\(\dfrac{n(n+1)}{2} < {{a}_{n}} < \dfrac{{{(n+1)}^{2}}}{2}\).

            • 4.

              用数学归纳法证明\(\left( {1}+\dfrac{{1}}{{3}} \right)\left( {1}+\dfrac{{1}}{{5}} \right)\left( {1}+\dfrac{{1}}{{7}} \right)\ldots \left( {1}+\dfrac{{1}}{{2}n-{1}} \right) > \dfrac{\sqrt{{2}n+{1}}}{{2}}(n∈N^{*}\)且\(n\geqslant 2)\)

            • 5. 设\(0 < \)\(a\)\(\leqslant \)\(b\)\(\leqslant \)\(c\)\(abc\)\(=1.\)试求\(\dfrac{1}{{a}^{2}(b+c)} \) \(+ \dfrac{1}{b^{3}(a+c)}+ \dfrac{1}{c^{3}(a+b)}\)的最小值.
            • 6.

              由函数不等式\(e^{x}\geqslant x+1(\)当且仅当\(x=0\)时取“\(=\)”\()\),可得  \((\)    \()\)

              A.\(\sum\limits_{k=1}^{n}{\dfrac{1}{n}} > \ln (n+1)\)
              B.\(\sum\limits_{k=1}^{n}{\dfrac{1}{n}} < \ln (n+1)\)
              C.\(\sum\limits_{k=1}^{n}{\dfrac{1}{n}}=\ln (n+{1})\)
              D.与\(n\)的值有关
            • 7.

              已知数列\(\{ a_{n}\}\)满足\(a_{1}{=}1\),\(a_{n{+}1}{=}\dfrac{a_{n}}{1{+}{a_{n}}^{2}}\),\(a_{n{+}1}{=}\dfrac{a_{n}}{1{+}{a_{n}}^{2}}.\)记\(S_{n}\),\(T_{n}\)分别是数列\(\{ a_{n}\}\),\(\{{a_{n}}^{2}\}\)的前\(n\)项和,证明:当\(n{∈}\mathbf{N}^{\mathbf{{*}}}\)时,

              \((1)a_{n{+}1}{ < }a_{n}\);

              \((2)T_{n}{=}\dfrac{1}{{a_{n{+}1}}^{2}}{-}2n{-}1\);

              \((3)\sqrt{2n}{-}1{ < }S_{n}{ < }\sqrt{2n}\).

            • 8.
              用反证法证明命题:“若\(a\),\(b∈N\),\(ab\)能被\(3\)整除,那么\(a\),\(b\)中至少有一个能被\(3\)整除”时,假设应为\((\)  \()\)
              A.\(a\),\(b\)都能被\(3\)整除
              B.\(a\),\(b\)都不能被\(3\)整除
              C.\(a\),\(b\)不都能被\(3\)整除
              D.\(a\)不能被\(3\)整除
            • 9.

              设\(S_{n}\)是数列\({a_{n}}\)的前\(n\)项和,\(a_{n} > 0\),且\(4S_{n}=a_{n}(a_{n}+2)\).

              \((\)Ⅰ\()\)求数列\({a_{n}}\)的通项公式;

              \((\)Ⅱ\()\)设\({{b}_{n}}=\dfrac{1}{({{a}_{n}}-1)({{a}_{n}}+1)}\),\(T_{n}=b_{1}+b_{2}+…+b_{n}\),求证:\({{T}_{n}} < \dfrac{1}{2}\).

            • 10. 设数列\(\{a_{n}\}\)满足:\(a_{1}=2,a_{n+1}=a_{n}+ \dfrac {1}{a_{n}}(n\in N^{*})\).
              \((1)\)证明:\(a_{n} > \sqrt {2n+1}\)对\(n∈N^{*}\)恒成立;
              \((2)\)令\(b_{n}= \dfrac {a_{n}}{ \sqrt {n}}(n\in N^{*})\),判断\(b_{n}\)与\(b_{n+1}\)的大小,并说明理由.
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