优优班--学霸训练营 > 知识点挑题
全部资源
          排序:
          最新 浏览

          50条信息

            • 1.
              如图\(1\),在高为\(2\)的梯形\(ABCD\)中,\(AB/\!/CD\),\(AB=2\),\(CD=5\),过\(A\)、\(B\)分别作\(AE⊥CD\),\(BF⊥CD\),垂足分别为\(E\)、\(F.\)已知\(DE=1\),将梯形\(ABCD\)沿\(AE\)、\(BF\)同侧折起,使得\(AF⊥BD\),\(DE/\!/CF\),得空间几何体\(ADE-BCF\),如图\(2\).

              \((\)Ⅰ\()\)证明:\(BE/\!/\)面\(ACD\);
              \((\)Ⅱ\()\)求三棱锥\(B-ACD\)的体积.
            • 2.
              如图,在三棱柱\(ABC-A_{1}B_{1}C_{1}\)中,底面\(ABC\)为正三角形,侧棱\(AA_{1}⊥\)底面\(ABC.\)已知\(D\)是\(BC\)的中点,\(AB=AA_{1}=2\).
              \((\)Ⅰ\()\)求证:平面\(AB_{1}D⊥\)平面\(BB_{1}C_{1}C\);
              \((\)Ⅱ\()\)求证:\(A_{1}C/\!/\)平面\(AB_{1}D\);
              \((\)Ⅲ\()\)求三棱锥\(A_{1}-AB_{1}D\)的体积.
            • 3.
              如图,已知四边形\(ABCD\)是正方形,\(PD⊥\)平面\(ABCD\),\(CD=PD=2EA\),\(PD/\!/EA\),\(F\),\(G\),\(H\)分别为\(PB\),\(BE\),\(PC\)的中点.
              \((I)\)求证:\(GH/\!/\)平面\(PDAE\);
              \((II)\)求证:平面\(FGH⊥\)平面\(PCD\).
            • 4.
              如图\(1\),在等腰直角三角形\(ABC\)中,\(∠A=90^{\circ}\),\(BC=6\),\(D\),\(E\)分别是\(AC\),\(AB\)上的点,\(CD=BE= \sqrt {2}\),\(O\)为\(BC\)的中点\(.\)将\(\triangle ADE\)沿\(DE\)折起,得到如图\(2\)所示的四棱椎\(A′-BCDE\),其中\(A′O= \sqrt {3}\).
              \((1)\)证明:\(A′O⊥\)平面\(BCDE\);
              \((2)\)求二面角\(A′-CD-B\)的平面角的余弦值.
            • 5.
              如图,点\(P\)是菱形\(ABCD\)所在平面外一点,\(∠BAD=60^{\circ}\),\(\triangle PCD\)是等边三角形,\(AB=2\),\(PA=2 \sqrt {2}\),\(M\)是\(PC\)的中点.
              \((\)Ⅰ\()\)求证:\(PA/\!/\)平面\(BDM\);
              \((\)Ⅱ\()\)求证:平面\(PAC⊥\)平面\(BDM\);
              \((\)Ⅲ\()\)求直线\(BC\)与平面\(BDM\)的所成角的大小.
            • 6.
              如图,三棱锥\(P-ABC\)中,平面\(PAC⊥\)平面\(ABC\),\(∠ABC= \dfrac {π}{2}\),点\(D\)、\(E\)在线段\(AC\)上,且\(AD=DE=EC=2\),\(PD=PC=4\),点\(F\)在线段\(AB\)上,且\(EF/\!/BC\).
              \((\)Ⅰ\()\)证明:\(AB⊥\)平面\(PFE\).
              \((\)Ⅱ\()\)若四棱锥\(P-DFBC\)的体积为\(7\),求线段\(BC\)的长.
            • 7.
              已知四棱锥\(P-ABCD\)中,底面\(ABCD\)是直角梯形,\(AB/\!/DC\),\(∠ABC=45^{\circ}\),\(DC=1\),\(AB=2\),\(PA⊥\)平面\(ABCD\),\(PA=1\).
              \((1)\)求证:\(AB/\!/\)平面\(PCD\);
              \((2)\)求证:\(BC⊥\)平面\(PAC\);
              \((3)\)若\(M\)是\(PC\)的中点,求三棱锥\(M-ACD\)的体积.
            • 8.

              如图,在四棱锥\(E{-}ABCD\)中,底面\(ABCD\)是边长为\(\sqrt{2}\)的正方形,平面\(AEC{⊥}\)平面\({CDE}{,}{∠}AEC{=}90^{{∘}}{,}F\)为\(DE\)中点,且\(DE{=}1\).


              \((\)Ⅰ\()\)求证:\(BE{/\!/}\)平面\(ACF\);
              \((\)Ⅱ\()\)求证:\(CD{⊥}DE\);
              \((\)Ⅲ\()\)求\(FC\)与平面\(ABCD\)所成角的正弦值.
            • 9.
              如图,在三棱台\({ABC}{-}A_{1}B_{1}C_{1}\)中,\(D{,}E\)分别是\({AB}{,}{AC}\)的中点,\({AB}{=}2A_{1}B_{1}{,}B_{1}E{⊥}\)平面\(ABC\),且\({∠}{ACB}{=}90^{{∘}}\).

              \((1)\)求证:\(B_{1}C{/\!/}\)平面\(A_{1}{DE}\);
              \((2)\)若\({AC}{=}3{BC}{=}6{,}{\triangle }AB_{1}C\)为等边三角形,求四棱锥\(A_{1}{-}B_{1}C_{1}{ED}\)的体积.
            • 10.

              如图\(1\),已知矩形\(ABCD\)中,点\(E\)是边\(BC\)上的点,\(AE\)与\(BD\)相交于点\(H\),且\(BE=\sqrt{{5}}\),\(AB={2}\sqrt{{5}}\),\(BC={4}\sqrt{{5}}\),现将\(\triangle ABD\)沿\(BD\)折起,如图\(2\),点\(A\)的位置记为\(A′\),此时\({A}{{{'}}}E=\sqrt{{17}}\).

              \((\)Ⅰ\()\)求证:\(BD⊥\)平面\(A′HE\);

              \((\)Ⅱ\()\)求三棱锥\(D-A′EH\)的体积.

            0/40

            进入组卷