优优班--学霸训练营 > 知识点挑题
全部资源
          排序:
          最新 浏览

          50条信息

            • 1. \(19.\)在平面直角坐标系\(xOy\)中,已知圆\(C\)的圆心在直线\(l\):\(4x-2y-5=0\)上.\((1)\)若圆\(C\)的半径为\(1\),圆心\(C\)也在直线\(y=x-1\)上,求圆\(C\)的方程;

              \((2)\)若圆\(C\)过坐标原点,证明圆\(C\)恒过异于原点\(O\)的另一个定点.

            • 2.

              \((1)\) 直线\(y=2x+3\)被圆\(x^{2}+y^{2}-6x-8y=0\)所截得的弦长等于 _________

              \((2)\)圆\({{(x-1)}^{2}}+{{(y+2)}^{2}}=3\)的一条弦的中点为\((\dfrac{1}{2},-\dfrac{3}{2})\),这条弦所在的直线方程为______

              \((3)\)已知圆系\(x^{2}+y^{2}-2ax+2(a-2)y+2=0(a\neq 1,a∈R)\),则该圆系恒过定点           

              \((4)\)一条光线从点\(A\left( -2,3 \right)\)射出,经过\(x\)轴反射后,与圆\(C:{{x}^{2}}+{{y}^{2}}-6x-4y+12=0\)相切,则反射光线所在直线的方程为                                

            • 3.
              过点\(M(2,-2)\)以及圆\(x^{2}+y^{2}-5x=0\)与圆\(x^{2}+y^{2}=2\)交点的圆的方程是\((\)  \()\)
              A.\(x^{2}+y^{2}- \dfrac {15}{4}x- \dfrac {1}{2}=0\)
              B.\(x^{2}+y^{2}- \dfrac {15}{4}x+ \dfrac {1}{2}=0\)
              C.\(x^{2}+y^{2}+ \dfrac {15}{4}x- \dfrac {1}{2}=0\)
              D.\(x^{2}+y^{2}+ \dfrac {15}{4}x+ \dfrac {1}{2}=0\)
            • 4.
              \({定义运算}:x⊗y= \begin{cases} \overset{x(x\geqslant y)}{y(x < y)}\end{cases}\;{例如}3⊗4=4\),则下列等式不能成立 的是\((\)  \()\)
              A.\(x⊗y=y⊗x\)
              B.\((x⊗y)⊗z=x⊗(y⊗z)\)
              C.\((x⊗y)^{2}=x^{2}⊗y^{2}\)
              D.\(c⋅(x⊗y)=(c⋅x)⊗(c⋅y)(\)其中\(c\)为常数\()\)
            • 5.
              已知曲线\(C\):\(x^{2}+y^{2}+2kx+(4k+10)y+10k+20=0\),其中\(k\neq -1\),则\(C\)过定点 ______ .
            0/40

            进入组卷