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            • 1.
              在等差数列\(\{{{a}_{n}}\}\) 中,\({{a}_{2}}=3\) \({{a}_{3}}+{{a}_{6}}=11\)
              \((\)Ⅰ\()\)求数列\(\{{{a}_{n}}\}\) 的通项公式;

              \((\)Ⅱ\()\)设\({{b}_{n}}={{a}_{n}}+\dfrac{1}{{{2}^{{{a}_{n}}}}}\),其中\(n\in {{\mathbf{N}}^{*}}\),求数列\(\{{{b}_{n}}\}\)的前\(n\)项和\({{S}_{n}}\)

            • 2.
              在等比数列\(\{a_{n}\}\)中,公比为\(q\),\(S_{n}\)为其前\(n\)项和\(.\)已知\(q=3\),\(S_{4}=80\),则\(a_{1}\)的值为 ______ .
            • 3.
              各项均为正数的等比数列\(\{a_{n}\}\),其前\(n\)项和为\(S_{n}\),若\(a_{2}-a_{5}=-78\),\(S_{3}=13\),则数列\(\{a_{n}\}\)的通项公式\(a_{n}=(\)  \()\)
              A.\(2^{n}\)
              B.\(B\)、\(2^{n-1}\)
              C.\(3^{n}\)
              D.\(3^{n-1}\)
            • 4.

              已知数列\(\left\{ {{a}_{n}} \right\}\)是各项均为正数的等比数列,且\({{a}_{2}}=1\)\({{a}_{3}}+{{a}_{4}}={6}\)

              \((\)Ⅰ\()\)求数列\(\left\{ {{a}_{n}} \right\}\)的通项公式;

              \((\)Ⅱ\()\)设数列\(\left\{ {{a}_{n}}-n \right\}\)的前\(n\)项和为\({{S}_{n}}\),比较\({{S}_{4}}\)和\({{S}_{5}}\)的大小,并说明理由.

            • 5.
              数列\(\{a_{n}\}\)中,\(a_{1}=2\),\(a_{n+1}=a_{n}+cn(c\)是不为零的常数,\(n=1\),\(2\),\(3\),\(…)\),且\(a_{1}\),\(a_{2}\),\(a_{3}\)成等比数列.
              \((1)\)求\(c\)的值;
              \((2)\)求\(\{a_{n}\}\)的通项公式;
              \((3)\)设数列\(\{ \dfrac {a_{n}-c}{n\cdot c^{n}}\}\)的前\(n\)项之和为\(T_{n}\),求\(T_{n}\).
            • 6.
              已知数列\(\{a_{n}\}\)满足\(a_{1}=3\),\(a_{n+1}=2a_{n}\),那么\(a_{4}=(\)  \()\)
              A.\(24\)
              B.\(18\)
              C.\(16\)
              D.\(12\)
            • 7.
              已知\(\{a_{n}\}\)为等比数列,\(S_{n}\)为其前\(n\)项和\(.a_{3}-a_{1}=15\),\(a_{2}-a_{1}=5\),则\(S_{4}=(\)  \()\)
              A.\(75\)
              B.\(80\)
              C.\(155\)
              D.\(160\)
            • 8.
              一个等比数列\(\{a_{n}\}\)的前\(n\)项和为\(48\),前\(2n\)项和为\(60\),则前\(3n\)项和为\((\)  \()\)
              A.\(63\)
              B.\(108\)
              C.\(75\)
              D.\(83\)
            • 9.
              设\(S_{n}\)为等比数列\(\{a_{n}\}\)的前\(n\)项和,\(8a_{12}-a_{15}=0\),则\( \dfrac {S_{4}}{S_{2}}=(\)  \()\)
              A.\(5\)
              B.\(8\)
              C.\(-8\)
              D.\(15\)
            • 10.
              已知等比数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),公比为\(q(q\neq 1)\),证明:\(S_{n}= \dfrac {a_{1}(1-q^{n})}{1-q}\).
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