优优班--学霸训练营 > 知识点挑题
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            • 1.
              已知\(F_{1}\)、\(F_{2}\)是椭圆\( \dfrac {x^{2}}{16}+ \dfrac {y^{2}}{9}=1\)的两焦点,经点\(F_{2}\)的直线交椭圆于点\(A\)、\(B\),若\(|AB|=5\),则\(|AF_{1}|+|BF_{1}|\)等于\((\)  \()\)
              A.\(16\)
              B.\(11\)
              C.\(8\)
              D.\(3\)
            • 2.
              如图,一圆形纸片的圆心为\(O\),\(F\)是圆内一定点,\(M\)是圆周上一动点,把纸片折叠使\(M\)与\(F\)重合,然后抹平纸片,折痕为\(CD\),设\(CD\)与\(OM\)交于点\(P\),则点\(P\)的轨迹是\((\)  \()\)
              A.椭圆
              B.双曲线
              C.抛物线
              D.圆
            • 3.
              已知中心在原点的椭圆\(C\)的右焦点为\(F(1,0)\),离心率等于\( \dfrac {1}{2}\),则\(C\)的方程是\((\)  \()\)
              A.\( \dfrac {x^{2}}{3}+ \dfrac {y^{2}}{4}=1\)
              B.\( \dfrac {x^{2}}{4}+ \dfrac {y^{2}}{ \sqrt {3}}=1\)
              C.\( \dfrac {x^{2}}{4}+ \dfrac {y^{2}}{2}=1\)
              D.\( \dfrac {x^{2}}{4}+ \dfrac {y^{2}}{3}=1\)
            • 4.
              已知椭圆\(C\):\( \dfrac {x^{2}}{a^{2}}+ \dfrac {y^{2}}{b^{2}}=1(a > b > 0)\)的离心率为\( \dfrac { \sqrt {3}}{2}\),四个顶点构成的四边形的面积为\(12\),直线\(l\)与椭圆\(C\)交于\(A\),\(B\)两点,且线段\(AB\)的中点为\(M(-2,1)\),则直线\(l\)的斜率为\((\)  \()\)
              A.\( \dfrac {1}{3}\)
              B.\( \dfrac {3}{2}\)
              C.\( \dfrac {1}{2}\)
              D.\(1\)
            • 5.
              离心率\(e= \dfrac {2}{3}\),焦距\(2c=16\)的椭圆的标准方程为 ______ .
            • 6.
              已知椭圆\(C\)的两个焦点分别为\(F_{1}(-1,0)\)、\(F_{2}(1,0)\),短轴的两个端点分别为\(B_{1}\),\(B_{2}\)
              \((1)\)若\(\triangle F_{1}B_{1}B_{2}\)为等边三角形,求椭圆\(C\)的方程;
              \((2)\)若椭圆\(C\)的短轴长为\(2\),过点\(F_{2}\)的直线\(l\)与椭圆\(C\)相交于\(P\),\(Q\)两点,且\( \overrightarrow{F_{1}P}⊥ \overrightarrow{F_{1}Q}\),求直线\(l\)的方程.
            • 7.
              已知中心在坐标原点\(O\)的椭圆\(C\)经过点\(A(2,3)\),且点\(F(2,0)\)为其右焦点.
              \((\)Ⅰ\()\)求椭圆\(C\)的标准方程;
              \((\)Ⅱ\()\)是否存在平行于\(OA\)的直线\(l\),使得直线\(l\)与椭圆\(C\)有公共点,且直线\(OA\)与\(l\)的距离等于\(4\)?若存在,求出直线\(l\)的方程;若不存在,请说明理由.
            • 8.
              已知椭圆的中心为原点,离心率\(e= \dfrac { \sqrt {3}}{2}\),且它的一个焦点与抛物线\(x^{2}=-4 \sqrt {3}y\)的焦点重合,则此椭圆方程为\((\)  \()\)
              A.\(x^{2}+ \dfrac {y^{2}}{4}=1\)
              B.\( \dfrac {x^{2}}{4}+y^{2}=1\)
              C.\( \dfrac {x^{2}}{16}+ \dfrac {y^{2}}{4}=1\)
              D.\( \dfrac {x^{2}}{4}+ \dfrac {y^{2}}{16}=1\)
            • 9.
              已知\(F_{1}\)、\(F_{2}\)是椭圆\( \dfrac {x^{2}}{a^{2}}+ \dfrac {y^{2}}{b^{2}}=1\)的左、右焦点,\(O\)为坐标原点,点\(P(-1, \dfrac { \sqrt {2}}{2})\)在椭圆上,线段\(PF_{2}\)与\(y\)轴的交点\(M\)满足\( \overrightarrow{PM}+ \overrightarrow{F_{2}M}= \overrightarrow{0}\);
              \((1)\)求椭圆的标准方程;
              \((2)⊙O\)是以\(F_{1}F_{2}\)为直径的圆,一直线\(l\):\(y=kx+m\)与\(⊙O\)相切,并与椭圆交于不同的两点\(A\)、\(B.\)当\( \overrightarrow{OA}\cdot \overrightarrow{OB}=λ\)且满足\( \dfrac {2}{3}\leqslant λ\leqslant \dfrac {3}{4}\)时,求\(\triangle AOB\)面积\(S\)的取值范围.
            • 10.
              已知椭圆\(C\):\( \dfrac {x^{2}}{a^{2}}+ \dfrac {y^{2}}{b^{2}}=1(a > b > 0)\),过\(C\)上一点\((2 \sqrt {2}, \sqrt {2})\)的切线\(l\)的方程为\(x+2y-4 \sqrt {2}=0\).
              \((1)\)求椭圆\(C\)的方程.
              \((2)\)设过点\(M(0,1)\)且斜率不为\(0\)的直线交椭圆于\(A\),\(B\)两点,试问\(y\)轴上是否存在点\(P\),使得\( \overrightarrow{PM}=λ( \dfrac { \overrightarrow{PA}}{| \overrightarrow{PA}|}+ \dfrac { \overrightarrow{PB}}{| \overrightarrow{PB}|})\)?若存在,求出点\(P\)的坐标;若不存在说明理由.
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