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            • 1. 正方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中棱长为\(1\),则面\(A_{1}BD\)与底面\(ABCD\)所成的角余弦值为\((\)  \()\)
              A.\( \dfrac { \sqrt {3}}{3}\)
              B.\( \dfrac { \sqrt {3}}{2}\)
              C.\( \dfrac { \sqrt {6}}{3}\)
              D.\(- \dfrac { \sqrt {3}}{3}\)
            • 2.

              如图,在四棱锥\(P-ABCD\)中,\(PA⊥\)平面\(ABCD\),\(AD/\!/BC\),\(AD⊥CD\),且\(AD=CD=2 \sqrt{2} \),\(BC=4 \sqrt{2} \),\(PA=2\),点\(M\)在\(PD\)上.


              \((\)Ⅰ\()\)求证:\(AB⊥PC\);

              \((\)Ⅱ\()\)若二面角\(M-AC-D\)的大小为\(45^{\circ}\),求\(BM\)与平面\(PAC\)所成角的正弦值.

            • 3.
              正三棱锥\(P-ABC\)中,\(PA=3\),\(AB=2\),则\(PA\)与平面\(PBC\)所成角的余弦值为\((\)  \()\)
              A.\( \dfrac {2 \sqrt {3}}{9}\)
              B.\( \dfrac { \sqrt {6}}{12}\)
              C.\( \dfrac {7 \sqrt {2}}{12}\)
              D.\( \dfrac { \sqrt {2}}{4}\)
            • 4. 把正方形\(ABCD\)沿对角线\(AC\)折起,当以\(A\)、\(B\)、\(C\)、\(D\)四点为顶点的三棱锥体积最大时,直线\(BD\)和平面\(ABC\)所成的角的大小为\((\)  \()\)
              A.\(90^{\circ}\)
              B.\(60^{\circ}\)
              C.\(45^{\circ}\)
              D.\(30^{\circ}\)
            • 5.

              \(19.\)如图,在直角梯形\(A{{A}_{1}}{{B}_{1}}B\)中,\(\angle {{A}_{1}}AB=90{}^\circ \),\({{A}_{1}}{{B}_{1}}/\!/AB\),\({{A}_{1}}{{B}_{1}}=1\),\(AB=A{{A}_{1}}=2.\)直角梯形\(A{{A}_{1}}{{C}_{1}}C\)通过直角梯形\(A{{A}_{1}}{{B}_{1}}B\)以直线\(A{{A}_{1}}\)为轴旋转得到,且使得平面\(A{{A}_{1}}{{C}_{1}}C\bot \)平面\(A{{A}_{1}}{{B}_{1}}B\).


              \((1)\)求证:平面\(CA{{B}_{1}}\bot \)平面\(A{{A}_{1}}{{B}_{1}}B\);

              \((2)\)延长\({{B}_{1}}{{A}_{1}}\)至点\({{D}_{1}}\),使\({{B}_{1}}{{A}_{1}}={{A}_{1}}{{D}_{1}}\),\(E\)为平面\(ABC\)内的动点,若直线\({{D}_{1}}E\)与平面\(CA{{B}_{1}}\)所成的角为\(\alpha \),且\(\sin \alpha =\dfrac{2\sqrt{5}}{5}\),求点\(E\)到点\(B\)的距离的最小值.

            • 6. 已知在四棱锥\(P-ABCD\)中,底面\(ABCD\)是矩形,\(PA⊥\)平面\(ABCD\),\(E\)、\(F\)分别是\(AB\)、\(PD\)的中点,若二面角\(P-CD-A\)为\(60^{\circ}\),且\(AD=2\),\(AB=4\).
              \((\)Ⅰ\()\)求证:\(AF/\!/\)平面\(PEC\);
              \((\)Ⅱ\()\)求直线\(PA\)与平面\(PED\)所成角的正弦值.
            • 7.
              在长方体\(ABCD-A_{1}B_{1}C_{1}D_{1}\)中,\(AA_{1}=AD=2AB.\)若\(E\),\(F\)分别为线段\(A_{1}D_{1}\),\(CC_{1}\)的中点,则直线\(EF\)与平面\(ADD_{1}A_{1}\)所成角的正弦值为\((\)  \()\)
              A.\( \dfrac { \sqrt {6}}{3}\)
              B.\( \dfrac { \sqrt {2}}{2}\)
              C.\( \dfrac { \sqrt {3}}{3}\)
              D.\( \dfrac {1}{3}\)
            • 8.

              已知二面角\(α—PQ—β\)为\(\dfrac{\mathrm{ }\!\!\pi\!\!{ }}{3}\),\(A∈α\),\(B∈β\),\(C∈PQ\),\(R\)为线段\(A\)的中点,\(\angle ACP=\angle BCP=\dfrac{\mathrm{ }\!\!\pi\!\!{ }}{6}\),\(CA=CB=2\),则直线\(BR\)与平面\(α\)所成角的大小为________.

            • 9.

              如图所示,在三棱锥\(A-BCD\)中,\(AB\bot \)平面\(BCD\),\(AC=AD=2\),\(BC=BD=1\),点\(E\)是线段\(AD\)的中点.

              \((1)\)如果\(CD=\sqrt{2}\),求证:平面\(BCE\bot \)平面\(ABD\) .

              \((2)\)如果\(\angle CBD=\dfrac{2\pi }{3}\),求直线\(CE\)和平面\(BCD\)所成的角的余弦值.

            • 10.

              如图,四棱柱\(ABCD-A′B′C′D′\)中,侧棱\(AA′⊥ABCD\),\(AB/\!/DC\),\(AB⊥AD\),\(AD=CD=1\),\(AA′=AB=2\),\(E\)为棱\(AA′\)的中点.

              \((1)\)求证:\(B′C′⊥CE\);

              \((2)\)求二面角\(B′-CE-C′\)的余弦值;
              \((3)\)设点\(M\)在线段\(C′E\)上,且直线\(AM\)与平面\(ADD′A′\)所成角的正弦值为,求线段\(AM\)的长.

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