如图,斜三棱柱\(ABC-A_{1}B_{1}C_{1}\)中,平面\(ACC_{1}A_{1}⊥\)平面\(BCC_{1}B_{1}\),\(E\)为棱\(CC_{1}\)的中点,\(A_{1}B\)与\(AB_{1}\)交于点\(O.\)若\(AC=CC_{1}=2BC=2\),\(∠ACC_{1}=∠CBB_{1}=60^{\circ}\).
\((\)Ⅰ\()\)证明:直线\(OE/\!/\)平面\(ABC\);
\((\)Ⅱ\()\)证明:平面\(ABE⊥\)平面\(AB_{1}E\);
\((\)Ⅲ\()\)求直线\(A_{1}B\)与平面\(ABE\)所成角的正弦值.