优优班--学霸训练营 > 知识点挑题
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            • 1. 如图,四棱锥\(P-ABCD\)中,底面\(ABCD\)是直角梯形,\(AB/\!/CD\),\(∠DAB=60^{\circ}\),\(AB=AD=2CD\),侧面\(PAD⊥\)底面\(ABCD\),且\(\triangle PAD\)为等腰直角三角形,\(∠APD=90^{\circ}\),\(M\)为\(AP\)的中点.
              \((1)\)求证:\(AD⊥PB\);
              \((2)\)求证:\(DM/\!/\)平面\(PCB\).
            • 2. 如图在\(\triangle ABC\)中,\(AB= \dfrac {3 \sqrt {6}}{2}\),\(CD=5\),\(∠ABC=45^{\circ}\),\(∠ACB=60^{\circ}\),则\(AD=\)______.
            • 3.
              如图所示,在梯形\(ABCD\)中,\(CD=2\),\(AC= \sqrt {19}\),\(∠BAD=60^{\circ}\),求梯形的高.
            • 4.
              若\( \begin{pmatrix} 2 & 0 \\ -1 & 3\end{pmatrix} \begin{pmatrix} \overset{x}{y}\end{pmatrix}= \begin{pmatrix} \overset{-2}{7}\end{pmatrix}\),则\(x+y=\) ______ .
            • 5. 在\(\triangle ABC\)中,已知\(a=10\),\(∠B=45^{\circ}\),\(∠A=30^{\circ}\),解此三角形.
            • 6.

              在\(Rt\triangle \)\(ABC\)中,\(∠\)\(BAC=\)\(90^{\circ}\),\(AB=\)\(1\),\(BC=\)\(2\)\(BC\)边上任取一点\(M\),则\(∠\)\(AMB\)\(\geqslant 90^{\circ}\)的概率为                   

            • 7. 在\(\triangle ABC\)中,\(∠A\):\(∠B\):\(∠C=1\):\(2\):\(3\),\(CD⊥AB\)于\(D\),\(AB=a\),则\(DB=(\)  \()\)
              A.\( \dfrac {a}{4}\)
              B.\( \dfrac {a}{3}\)
              C.\( \dfrac {a}{2}\)
              D.\( \dfrac {3a}{4}\)
            • 8.
              选做题:平面几何
              已知在\(\triangle ABC\)中,\(AB=AC\),以\(AB\)为直径的\(⊙O\)交\(BC\)于\(D\),过\(D\)点作\(⊙O\)的切线交\(AC\)于\(E\).
              求证:\((1)DE⊥AC\);\(\)
              \((2)BD^{2}=CE⋅CA\).
            • 9.
              \(\triangle ABC\)中,\(∠BAC=90^{\circ}\),\(AD⊥BC\),垂足为\(D.\)若\(BC=m\),\(∠B=α\),则\(AD\)长为\((\)  \()\)
              A.\(m\sin ^{2}α\)
              B.\(m\cos ^{2}α\)
              C.\(m\sin α\cos α\)
              D.\(m\sin α\tan α\)
            • 10.
              如图所示,在平面四边形\(ABCD\)中,\(AB⊥AD\),\(∠ADC= \dfrac {2π}{3}\),\(E\)为\(AD\)边上一点,\(CE= \sqrt {7}\),\(DE=1\),\(AE=2\),\(∠BEC= \dfrac {π}{3}\).
              \((\)Ⅰ\()\)求\(\sin ∠CED\)的值;
              \((\)Ⅱ\()\)求\(BE\)的长.
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