优优班--学霸训练营 > 知识点挑题
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            • 1.
              等比数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),且\(4a_{1}\),\(2a_{2}\),\(a_{3}\)成等差数列\(.\)若\(a_{1}=1\),则\(S_{4}=(\)  \()\)
              A.\(15\)
              B.\(7\)
              C.\(8\)
              D.\(16\)
            • 2.
              等比数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),已知\(S_{3}=a_{2}+10a_{1}\),\(a_{5}=9\),则\(a_{1}=(\)  \()\)
              A.\( \dfrac {1}{3}\)
              B.\(- \dfrac {1}{3}\)
              C.\( \dfrac {1}{9}\)
              D.\(- \dfrac {1}{9}\)
            • 3.
              已知等比数列\(\{a_{n}\}\)的前\(n\)项和为\(S_{n}\),若\(S_{2}=3\),\(S_{4}=15\),则\(S_{8}=(\)  \()\)
              A.\(127\)
              B.\(192\)
              C.\(255\)
              D.\(511\)
            • 4.
              等比数列\(\{a_{n}\}\)中,满足\(a_{1}=2\),公比\(q=2.\)则数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}=\) ______ .
            • 5.
              数列\(\{a_{n}\}\)是公比为\(2\)的等比数列,其前\(n\)项和为\(S_{n}.\)若\(a_{2}= \dfrac {1}{2}\),则\(a_{n}=\) ______ ;\(S_{5}=\) ______ .
            • 6.
              已知数列\(\{a_{n}\}\)为等比数列,若\(a_{5}=2\),则数列\(\{a_{n}\}\)的前\(9\)项之积\(T_{9}\)等于\((\)  \()\)
              A.\(512\)
              B.\(256\)
              C.\(128\)
              D.\(64\)
            • 7.
              已知等比数列\(\{a_{n}\}\)中,\(a_{1}=a_{8}=3\),则其前\(n\)项和\(S_{n}(\)  \()\)
              A.\( \dfrac {3}{2}(3^{n}-1)\)
              B.\(n^{2}\)
              C.\(3^{n}\)
              D.\(3n\)
            • 8.
              已知等比数列\(\{a_{n}\}\)中,\(a_{2}=2\),则其前三项和\(S_{3}\)的取值范围是\((\)  \()\)
              A.\((-∞,-2]\)
              B.\((-∞,0)∪(1,+∞)\)
              C.\([6,+∞)\)
              D.\((-∞,-2]∪[6,+∞)\)
            • 9.
              若等比数列\(\{a_{n}\}\)满足\(a_{2}+a_{4}=20\),\(a_{3}+a_{5}=40\),则数列\(\{a_{n}\}\)的前\(n\)项和\(S_{n}=\) ______ .
            • 10.
              我国古代数学著作\(《\)九章算术\(》\)有如下问题:“今有蒲\((\)水生植物名\()\)生一日,长三尺;莞\((\)植物名,俗称水葱、席子草\()\)生一日,长一尺\(.\)蒲生日自半,莞生日自倍\(.\)问几何日而长等?”意思是:今有蒲生长\(1\)日,长为\(3\)尺;莞生长\(1\)日,长为\(1\)尺\(.\)蒲的生长逐日减半,莞的生长逐日增加\(1\)倍\(.\)若蒲、莞长度相等,则所需的时间约为 ______ 日\(.(\)结果保留一位小数,参考数据:\(\lg 2≈0.30\),\(\lg 3≈0.48)\)
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